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How to convert matrices of different sizes in a for loop into a single column vector?

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Anisia Anil
Anisia Anil 2022-12-5
回答： Bruno Luong 2023-1-16
A = imread('Ish.JPG');
A = im2single(squeeze(mean(A,3)));
A = im2double(A);
[pyrRef,pind] = buildLpyr(A,'auto');
nLevels = 7;
kernelx = [0.0, 0.0, 0.0; 0.5, 0.0, -0.5; 0.0, 0.0, 0.0];
kernely = [0.0, 0.5, 0.0; 0.0, 0.0, 0.0; 0.0, -0.5, 0.0];
for k = 1:nLevels
subband = pyrBand(pyrRef, pind, k);
rx(k) = conv2(subband(k),kernelx);
ry(k) = conv2(subband(k),kernely);
amp = sqrt(subband.^2 + rx(k).^2 + ry(k).^2);
Phase = acos(subband./amp);
end
Here, the value of "Phase" is a matrix with varying dimension at each iteration of 'k'. How do I save all the values in these k matrices into a single coloumn vector?
  2 个评论
Jiri Hajek
Jiri Hajek 2022-12-5
编辑：Jiri Hajek 2022-12-5
Hi, you can make column vector from a matrix by using linear indexing
columnVector = Array(:);
And if by "save all" you mean to concatenate these vectors, then its possible simply by using brackets:
concatenatedVectors = [firstVector; secondVector];

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回答（3 个）

Jan
Jan 2022-12-5
...
PhaseC = cell(1, nLevels);
for k = 1:nLevels
...
PhaseC{k} = acos(subband./amp);
end
Phase = cat(2, PhaseC{:}); % Maybe cat(1, ...
MFK
MFK 2023-1-16
https://www.mathworks.com/help/matlab/ref/reshape.html
for k = 1:nLevels
...
Phase = acos(subband./amp);
re_shaped_Phas{k,1}=reshape(Phase,1,[]);
end
Bruno Luong
Bruno Luong 2023-1-16
...
PhaseC = cell(1, nLevels);
for k = 1:nLevels
...
Phase = acos(subband./amp);
PhaseC{k} = Phase(:);
end
Phase = cat(1, PhaseC{:});

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