drawing a point in the graph

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Ismita
Ismita 2022-12-6
评论: Ismita 2022-12-7

回答(2 个)

Arif Hoq
Arif Hoq 2022-12-6
编辑:Arif Hoq 2022-12-6
x = 1:5;
y = 20:24;
plot(x,y,x(3),y(3),'*') % specify a marker symbol * in index 3 of y
please follow this for more information about plot
  3 个评论
Arif Hoq
Arif Hoq 2022-12-7
try this approach. I am not sure about his efficiency.
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
[x1equality ia]=find(ismember(t1,t2));
[x3equality ib]=find(ismember(t3,t4));
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g',x1(ia),t1(ia),'*',x3(ib),t3(ib),'*')

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Walter Roberson
Walter Roberson 2022-12-6
x = 0:0.5:10;
t = (x/2).^2;
abs(x-2*sqrt(t)) %cross-check weether x == 2*sqrt(t)
ans = 1×21
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
plot(x, t, '*-')
  5 个评论
Walter Roberson
Walter Roberson 2022-12-7
plot(6.78233, 11.66, 'r*')
It does not matter if there is no exact match for this in the curves, if it is the correct intersection point.
Unless, that is, what you want to do is find the closest point on each of the two curves and mark those close points rather than the intersection point?

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