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I am having this error, could you help?

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Demberel
Demberel 2022-12-7
回答： Voss 2022-12-7
a=[1.6];
b=[0];
x(1)=1.28; x(2)=1.36; x(3)=2.47; x(4)=3.68; x(5)=4.56;
for i=1:5
y(i)=a.^(x.^2-1)-log(x.^2-1)+(x.^2).^(1/3);
end
y

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回答（2 个）

Arif Hoq
Arif Hoq 2022-12-7
编辑：Arif Hoq 2022-12-7
Ran in:
try this:
a=1.6;
b=0;
% x(1)=1.28;
% x(2)=1.36;
% x(3)=2.47;
% x(4)=3.68;
% x(5)=4.56;
x=[1.28;1.36;2.47;3.68;4.56];
for i=1:size(x,1)
y(i)=a^(x(i)^2-1)-log(x(i)^2-1)+(x(i)^2).^(1/3);
end
y
y = 1×5
1.0e+04 * 0.0003 0.0003 0.0011 0.0363 1.0971
  1 个评论
Askic V
Askic V 2022-12-7
Even better, use
for iii=1:numel(x)
This way if you add more/remove elements in vector x, you won't have to change te limit in the for loop.

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Voss
Voss 2022-12-7
Ran in:
a=1.6;
b=0;
x=[1.28 1.36 2.47 3.68 4.56];
y=a.^(x.^2-1)-log(x.^2-1)+(x.^2).^(1/3);
y
y = 1×5
1.0e+04 * 0.0003 0.0003 0.0011 0.0363 1.0971

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