Is there any other way to find Transfer function H(z) for an IIR Butterworth Filter?

5 次查看（过去 30 天）
Aryan S. Rajeev
Aryan S. Rajeev 2022-12-10
回答： Sai 2022-12-28
close all;
clc;clear all;
%ButterWorth IIR LowPass Filter
Rp=input('Enter PassBand Ripple:');
As=input('Enter Stopband Ripple:');
wp=input('Enter Digital Passband Frequency:');
ws=input ('Enter Digital Stopband Frequency:');
T = input('Enter the Sampling Time Period in Seconds:');
%PreWarping these frequencies into digital domain
omegap = (2/T)*tan(wp/2);
omegas = (2/T)*tan(ws/2);
%Calculating order
num=log10((10^(0.1*Rp)-1)/((10^(0.1*As)-1)));
den=2*log10(omegap/omegas);
N=ceil(num/den);
%Calculating Cut off Frequencies
x1=(10^(0.1*Rp)-1);
x2=(10^(0.1*As)-1);
pow=1/(2*N);
omegac1=omegap/(x1^(pow));
omegac2=omegas/(x2^pow);
omegac=(omegac1+omegac2)/2;
%Calculating Poles
limit=((2*N)-1);
p1=zeros(1,limit+1);
for k=0:limit
pow1=(1j*pi)/(2*N);
e=exp(pow1*((2*k)+N+1));
p1(k+1)=omegac*e;
end
p=zeros(1,N);
%Selection of left Half plane Poles
for k=0:limit
if(real(p1(k+1))<0)
p(k+1)=p1(k+1);
end
end
%Determining Analog Prototype Filter Transfer Function Ha(s)
syms s z
den1=1;
num1=omegac^N;
lt=length(p);
for g=1:lt
den1=den1*(s-p(g));
end
Ha=num1/den1;
%Bilinear Transformation
H=subs(Ha,s,(2/T)*(z-1)/(z+1));
H gives the tranfer function , but the z terms are just as it is. The desired result is that it should be in terms of z^2, z^3 ... etc
Is there any other way to obtain transfer function H(z)? Also How can i find difference equation from H(z)?
  3 个评论
显示 1更早的评论
Star Strider
Star Strider 2022-12-11
Ran in:
One missing item are the units of the inputs. I partially corrected for them here, although the magnitude (checked using the freqz function) is still not correct. I leave those to you.
% close all;
% clc;clear all;
% % % SPECIFICATIONS: Rp = 1 Db, As = 50 dB, wp = 10 Hz, ws = 20 Hz, Fs = 100 Hz
%ButterWorth IIR LowPass Filter
% Rp=input('Enter PassBand Ripple:');
% As=input('Enter Stopband Ripple:');
% wp=input('Enter Digital Passband Frequency:');
% ws=input ('Enter Digital Stopband Frequency:');
% T = input('Enter the Sampling Time Period in Seconds:');
Rp = db2mag(-1); % Convert From dB To Magnitude
As = db2mag(-50); % Convert From dB To Magnitude
T = 0.01; % Sampling Interval (1/Fs)
wp = 10*pi*T*2; % Converted From Hz To rad/s & Corrected For Nyquist Frequency
ws = 20*pi*T*2; % Converted From Hz To rad/s & Corrected For Nyquist Frequency
%PreWarping these frequencies into digital domain
omegap = (2/T)*tan(wp/2);
omegas = (2/T)*tan(ws/2);
%Calculating order
num=log10((10^(0.1*Rp)-1)/((10^(0.1*As)-1)))
num = 2.4952
num = abs(num)
num = 2.4952
den=2*log10(omegap/omegas)
den = -0.6990
den = abs(den)
den = 0.6990
N=ceil(num/den)
N = 4
%Calculating Cut off Frequencies
x1=(10^(0.1*Rp)-1);
x2=(10^(0.1*As)-1);
pow=1/(2*N);
omegac1=omegap/(x1^(pow));
omegac2=omegas/(x2^pow);
omegac=(omegac1+omegac2)/2;
%Calculating Poles
limit=((2*N)-1);
p1=zeros(1,limit+1);
for k=0:limit
pow1=(1j*pi)/(2*N);
e=exp(pow1*((2*k)+N+1));
p1(k+1)=omegac*e;
end
p=zeros(1,N);
%Selection of left Half plane Poles
for k=0:limit
if(real(p1(k+1))<0)
p(k+1)=p1(k+1);
end
end
%Determining Analog Prototype Filter Transfer Function Ha(s)
syms s z
den1=1;
num1=omegac^N;
lt=length(p);
for g=1:lt
den1=den1*(s-p(g));
end
Ha=num1/den1;
%Bilinear Transformation
H=subs(Ha,s,(2/T)*(z-1)/(z+1))
H = 
[Hn,Hd] = numden(H)
Hn = 
Hd = 
Hnn = sym2poly(Hn)
Hnn = 1×5
1.0e+64 * 0.6966 2.7865 4.1797 2.7865 0.6966
Hnd = sym2poly(Hd)
Hnd =
1.0e+64 * 6.2490 - 0.0000i 1.3617 - 0.0000i 3.1310 - 0.0000i 0.2881 - 0.0000i 0.1161 - 0.0000i
figure
freqz(Hnn, Hnd, 2^16, 1/double(T))
set(subplot(2,1,1), 'YLim',[-10 0]) % Zoom Y-Axis Of Magnitude Plot (Optional)
.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Sai
Sai 2022-12-28
I understand that you are trying to get your final transfer function in powers of z. With small changes in code without modifying your logic, you can get it as shown in below code snippet.
close all;
clc;clear all;
%ButterWorth IIR LowPass Filter
Rp=input('Enter PassBand Ripple:');
As=input('Enter Stopband Ripple:');
wp=input('Enter Digital Passband Frequency:');
ws=input ('Enter Digital Stopband Frequency:');
T = input('Enter the Sampling Time Period in Seconds:');
%PreWarping these frequencies into digital domain
omegap = (2/T)*tan(wp/2);
omegas = (2/T)*tan(ws/2);
%Calculating order
num=log10((10^(0.1*Rp)-1)/((10^(0.1*As)-1)));
den=2*log10(omegap/omegas);
N=abs(ceil(num/den));
%Calculating Cut off Frequencies
x1=(10^(0.1*Rp)-1);
x2=(10^(0.1*As)-1);
pow=1/(2*N);
omegac1=omegap/(x1^(pow));
omegac2=omegas/(x2^pow);
omegac=(omegac1+omegac2)/2;
%Calculating Poles
limit=((2*N)-1);
p1=zeros(1,limit+1);
for k=0:limit
pow1=(1j*pi)/(2*N);
e=exp(pow1*((2*k)+N+1));
p1(k+1)=omegac*e;
end
p=zeros(1,N);
%Selection of left Half plane Poles
for k=0:limit
if(real(p1(k+1))<0)
p(k+1)=p1(k+1);
end
end
num1=omegac^N;
den1 = p;
%Bilinear Transformation
[zd,pd] = bilinear(num1,den1,1,T)
H = (tf(zd,pd,T))
There are direct MATLAB functions like buttord (for determining filter order and cutoff frequency), butter(for obtaining filter coefficients), bilinear (for converting analog to digital) by which you can design Butterworth filters. Refer to the below documentation pages for more information

类别

在 Help Center 和 File Exchange 中查找有关 Butterworth 的更多信息

标签

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by