unit step disturbance at a time of 40 seconds

12 次查看(过去 30 天)
How do I generate a unit step disturbance at a time of 40 seconds for my PID controller
clear all;
s=tf('s');
load time.dat;
load response.dat;
K = 2;
Tau = 3;
dt = 0.9;
g = ((2/(3*s + 1))*(exp(-dt*s)))
[gy,tg]=step(g,20)
plot(time, response,'k',tg,gy,'r','LineWidth',2)
hold on
% Cohen - Coon PI tuning
Kc = (1/K)*(Tau/dt)*(0.9 + (dt/(12*Tau)));
Tau_1 = (dt)*((30 + 3*(dt/Tau))/(9+20*(dt/Tau)));
P = Kc;
I = Kc/Tau_1;
cont = ((s*P + I)/s);
gol = cont*g
gcl = feedback(gol,1)
step(gcl,20)
hold on
grid on
Thanks

回答(1 个)

Sam Chak
Sam Chak 2022-12-12
编辑:Sam Chak 2022-12-12
The closed-loop transfer function for Y(s)/D(s) is given by
The following shows how to compute the comparison between the step responses for 40 seconds. Let us know if this is the technical answer that you are looking for.
s = tf('s');
% Parameters
K = 2;
Tau = 3;
dt = 0.9;
% Plant
Gp = ((2/(3*s + 1))*(exp(-dt*s)));
% Cohen - Coon PI tuning
Kc = (1/K)*(Tau/dt)*(0.9 + (dt/(12*Tau)));
Tau_1 = (dt)*((30 + 3*(dt/Tau))/(9 + 20*(dt/Tau)));
Kp = Kc;
Ki = Kc/Tau_1;
Gc = ((Kp*s + Ki)/s);
% Response to the Unit Step Reference
Gol = Gc*Gp;
Gcl = feedback(Gol, 1); % closed-loop transfer function Y(s)/R(s)
step(Gcl, 40)
hold on
% Response to the Unit Step Disturbance
Gcd = feedback(Gp, Gc); % closed-loop transfer function Y(s)/D(s)
step(Gcd, 40)
legend('Step Reference Response', 'Step Disturbance Response')
hold off, grid on

类别

Help CenterFile Exchange 中查找有关 Classical Control Design 的更多信息

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by