A table of s versus t.

1 次查看（过去 30 天）
jay jay
jay jay 2022-12-12
编辑： Davide Masiello 2022-12-12
Trying to make a table of s versus t and printing the results to both the screen and to the file.
r = 9 cm, ω = 100 revolutions per second, and b = 14 cm.
0 ≤ t ≤ 0.01 s. Using 20 subdivisions on the t
domain.
r=9
omega=100
b=14
t=0:20:0.01
s(t) = r* cos(2*pi*omega*t)+ sqrt((b^2)-(r^2)*(sin(2*pi*omega*t)^2))
table(s,t)
what is wrong with this code?

请先登录，再回答此问题。

回答（2 个）

Les Beckham
Les Beckham 2022-12-12
编辑：Les Beckham 2022-12-12
Ran in:
r=9;
omega=100;
b=14;
t = linspace(0, 0.01, 20) % <<< use linspace instead to generate your t vector
t = 1×20
0 0.0005 0.0011 0.0016 0.0021 0.0026 0.0032 0.0037 0.0042 0.0047 0.0053 0.0058 0.0063 0.0068 0.0074 0.0079 0.0084 0.0089 0.0095 0.0100
% remove the (t) on the left side and use .^2 to do element-wise operation
s = r* cos(2*pi*omega*t)+ sqrt((b^2)-(r^2)*(sin(2*pi*omega*t).^2))
s = 1×20
23.0000 22.2040 19.9647 16.7222 13.1584 10.0063 7.7015 6.2396 5.4133 5.0442 5.0442 5.4133 6.2396 7.7015 10.0063 13.1584 16.7222 19.9647 22.2040 23.0000
table(s,t)
ans = 1×2 table
s t ___________ ___________ 1×20 double 1×20 double
Davide Masiello
Davide Masiello 2022-12-12
编辑：Davide Masiello 2022-12-12
Ran in:
There are a couple of errors in your code.
First, the way you define the array t.
Second, for array operations, use the dot notation.
Third, no need to specify the s dependence on t.
r = 9;
omega = 100;
b = 14;
t = linspace(0,0.01,20)';
s = r*cos(2*pi*omega*t)+sqrt(b^2-(r^2)*sin(2*pi*omega*t).^2);
table(s,t)
ans = 20×2 table
s t ______ __________ 23 0 22.204 0.00052632 19.965 0.0010526 16.722 0.0015789 13.158 0.0021053 10.006 0.0026316 7.7015 0.0031579 6.2396 0.0036842 5.4133 0.0042105 5.0442 0.0047368 5.0442 0.0052632 5.4133 0.0057895 6.2396 0.0063158 7.7015 0.0068421 10.006 0.0073684 13.158 0.0078947
It seems like you might be new to Matlab, so I suggest reading some of the basic documentation. e.g.
https://ch.mathworks.com/learn/tutorials/matlab-onramp.html

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by