清空筛选条件
清空筛选条件

please anyone convert this c++ code into MATLAB

2 次查看（过去 30 天）
tina jain
tina jain 2015-3-25
编辑： James Tursa 2015-3-25
#include<stdio.h>
#include<iostream.h>
#include<conio.h>
#include<string.h>
void main()
{
int i,j,cnt,l,count[50];
char str[50];
clrscr();
printf("Enter the string");
scanf("%s",str);
printf("\n\t original s]==string is:%s",str);
printf("\n\n\t encoded string is:");
for(i=0;i<l;i=i*1)
{
j=0;
count[i]=1;
do
{
j++;
if(str[i+j]==str[i])
count[i]++;
}
while(str[i+j]==str[i]);
if(count[i]==1)
printf("%c",str[i++]);
else
{
printf("%c%d",str[i],count[i]);
i=i+count[i];
}
}
getch();
}
  2 个评论
James Tursa
James Tursa 2015-3-25
for(i=0;i<l;i=i*1)
In the above line, you use variable l before it is defined. Is l supposed to be the length of the string str?
Also, the last part of this for construct is i=i*1, which will essentially do nothing. Is this intended? If you want to do nothing here, then typically one would leave that part blank rather than put in code that accomplishes nothing.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

James Tursa
James Tursa 2015-3-25
编辑：James Tursa 2015-3-25
Making assumption that l is the string length (a really BAD choice for a variable name btw), here is a fairly literal translation. The functionality appears to simply count repeated letters and put that count into the output string, so this whole thing could probably be rewritten using that knowledge (but I am not going to do that for you here).
function estring(str)
l = numel(str);
i = 0;
count = zeros(1,l);
while( i < l )
j=0;
count(i+1) = 1;
while( true )
j = j + 1;
if( i+j+1 > l )
break;
end
if( str(i+j+1)==str(i+1) )
count(i+1) = count(i+1) + 1;
else
break;
end
end
if( count(i+1)==1 )
fprintf('%c',str(i+1)); i = i + 1;
else
fprintf('%c%d',str(i+1),count(i+1));
i = i + count(i+1);
end
end
fprintf('\n');
end
E.g.,
>> estring('abcdef')
abcdef
>> estring('aabbbcdeeeeef')
a2b3cde5f
>> estring('abcccdefggggggggggggggggggggg')
abc3defg21

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by