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Voss
Voss 2022-12-13
Ran in:

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Ran in:
% your matrix:
i = 0; m = 1; j = 2; n = 3;
M = repmat([i i i m m j j j n n],4,1)
M = 4×10
0 0 0 1 1 2 2 2 3 3 0 0 0 1 1 2 2 2 3 3 0 0 0 1 1 2 2 2 3 3 0 0 0 1 1 2 2 2 3 3
% delete columns 4-5 and 9-10:
M(:,[4 5 9 10]) = []
M = 4×6
0 0 0 2 2 2 0 0 0 2 2 2 0 0 0 2 2 2 0 0 0 2 2 2

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How can i mak it in a loop for (m*n) matrix?
Voss
Voss 2022-12-14
Why do you want to do that?
Because my matrix size is not fixed. But every time I need to delete two column after the equal number of column interval.
Voss
Voss 2022-12-14
Ran in:
Ran in:
Suppose you want to delete columns 4, 9, 14, ... and columns 5, 10, 15, ...
M = reshape(1:100,4,[])
M = 4×25
1 5 9 13 17 21 25 29 33 37 41 45 49 53 57 61 65 69 73 77 81 85 89 93 97 2 6 10 14 18 22 26 30 34 38 42 46 50 54 58 62 66 70 74 78 82 86 90 94 98 3 7 11 15 19 23 27 31 35 39 43 47 51 55 59 63 67 71 75 79 83 87 91 95 99 4 8 12 16 20 24 28 32 36 40 44 48 52 56 60 64 68 72 76 80 84 88 92 96 100
spacing = 5;
N_Cols = size(M,2);
col_to_delete = [4:spacing:N_Cols 5:spacing:N_Cols];
M(:,col_to_delete) = []
M = 4×15
1 5 9 21 25 29 41 45 49 61 65 69 81 85 89 2 6 10 22 26 30 42 46 50 62 66 70 82 86 90 3 7 11 23 27 31 43 47 51 63 67 71 83 87 91 4 8 12 24 28 32 44 48 52 64 68 72 84 88 92
No loop necessary.

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