how to split 6x4 double based on first columns values into three [2X4]?

A=[4 1 2 3
4 5 6 7
5 1 2 3
5 4 5 6 
5 4 5 6
5 4 5 6 
6 1 2 3
6 4 5 6];
A=unique(A,'rows');
Acell=splitapply(@(x){x}, A,findgroups(A(:,1)));
Acell{:}
ans = 2×4
     4     1     2     3
     4     5     6     7
ans = 2×4
     5     1     2     3
     5     4     5     6
ans = 2×4
     6     1     2     3
     6     4     5     6

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Answer 2

Matt J 2022-12-16

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1879867-how-to-split-6x4-double-based-on-first-columns-values-into-three-2x4#answer_1129682

编辑：Matt J 2022-12-16

在 MATLAB Online 中打开

A=randi(9,6,4)
A = 6×4
     6     1     9     7
     8     5     8     9
     9     7     9     9
     6     4     1     4
     6     7     7     9
     3     8     1     2
Acell=mat2tiles(A,[2,4]); %get mat2tiles from https://www.mathworks.com/matlabcentral/fileexchange/35085-mat2tiles-divide-array-into-equal-sized-sub-arrays
Acell{:}
ans = 2×4
     6     1     9     7
     8     5     8     9
ans = 2×4
     9     7     9     9
     6     4     1     4
ans = 2×4
     6     7     7     9
     3     8     1     2

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MS 2022-12-16

编辑：MS 2022-12-16

Thanks @Matt J sorry for the mis commmunciation. if you see the three splitted/grouped matrices are based on the fitst column values. I mean, it should be grouped based on the first column values such as 4, 5, 6.

All matrices should be grouped based on the first column values. 1, all matcies with 4 should be sperate matrix 2, all matrix with 5 should be sperate matrix 3, all matcies with 6should be sperate matrix etc.,

my matrix is not random.

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