How to find the index of array that reach to an specific value

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Hi everyone I have an array like this :
Columns 1 through 9
0 0 2 4 4 5 5 5 5
Columns 10 through 18
5 4 5 5 2 3 6 5 5
Columns 19 through 27
4 4 2 10 3 6 4 5 5
Column 28
2
and I want to calculate when in this array sum of how many of this element reaches to 10 and we can see in index 5 it reaches 10 then A = 5*T
I use cumsum for it and it gives me answer in first step
but again I don't know how to calculate the continue I mean that I want to calculate when again after index 5 the sum of element reach to 10 .
can anyone help me with it
  2 个评论
Torsten
Torsten 2022-12-17
I use cumsum for it and it gives me answer in first step
but again I don't know how to calculate the continue I mean that I want to calculate when again after index 5 the sum of element reach to 10
Then look up when cumsum reaches 20.
the cyclist
the cyclist 2022-12-17
@arash rad, suppose when you reach a value of at least 10, you actually get the value 14 (not exactly 10). Do you want to include that "extra" 4 as you sum toward 20, or start over from 0 for the next sum?

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回答(1 个)

Image Analyst
Image Analyst 2022-12-17
How about this:
v = randi(9, 1, 20)
v = 1×20
8 5 5 4 2 3 7 5 5 5 6 2 6 6 3 7 1 8 3 9
c = cumsum(v)
c = 1×20
8 13 18 22 24 27 34 39 44 49 55 57 63 69 72 79 80 88 91 100
thresholds = 10 : 10 : 10*length(c)
thresholds = 1×20
10 20 30 40 50 60 70 80 90 100 110 120 130 140 150 160 170 180 190 200
for k = 1 : length(c)
t = find(c >= thresholds(k), 1, 'first');
if ~isempty(t)
indexes(k) = t;
end
end
% Show indexes
indexes
indexes = 1×10
2 4 7 9 11 13 15 17 19 20
% Show cumulative sums at those indexes.
cumValues = c(indexes)
cumValues = 1×10
13 22 34 44 55 63 72 80 91 100
If it's not what you want, explain in detail why it's not.

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