Integration limit is an array

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syms x
tau=35*10^-15;
f=tau.*exp(-x.^(2));
t=linspace(-300*10^-15,300*10^-15,500);
fun=matlabFunction(f,'Vars',x);
z=integral(fun,-Inf,(t/tau),'ArrayValued',true)
Error using integral
Limits of integration must be double or single scalars.

采纳的回答

VBBV
VBBV 2022-12-22
syms x
tau=35*10^-15;
f=tau.*exp(-x.^(2));
t=linspace(-300*10^-15,300*10^-15,500);
fun=matlabFunction(f,'Vars',x)
fun = function_handle with value:
@(x)exp(-x.^2).*3.5e-14
for k = 1:length(t)
z(k)=integral(fun,-Inf,(t(k)/tau),'ArrayValued',true);
end
z
z = 1×500
1.0e-13 * 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000 0.0000
plot(t,z)
  1 个评论
VBBV
VBBV 2022-12-22
As mentioned in error, use scalar inputs to function integral

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