why the histogram wont show in the wanted axes the code has no errors but it wont show

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jana 2022-12-22

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评论： Walter Roberson 2023-1-10

采纳的回答： Walter Roberson

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Answer 1

Walter Roberson 2023-1-9

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When you have no output variable for imhist() and you do not tell it which axes to display into, then it will call gca() to find the current axes. gca() will not look for axes whose handle visibility is turned off, but by default handle visibility is off for all uiaxes in app designer.

You need to either turn on handle visibility for the target axes and make it the current axes (not recommended), or else you have to pass the target axes to imhist (recommended)

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jana 2023-1-10

but i thought i did tell it which axes to show up in i dont know this is the code

a =app.Image;

o=im2gray(a);

c=imhist(o);

I=imshow(c,'parent',app.UIAxes2,...

'XData',[1 app.UIAxes2.Position(3)],...

'YData',[1 app.UIAxes2.Position(4)]);

app.UIAxes2.XLim=[0 I.XData(2)];

app.UIAxes2.YLim=[0 I.YData(2)];

Walter Roberson 2023-1-10

histforrgbbutton has imhist() with no output and no axes.

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Answer 2

Image Analyst 2022-12-23

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在 MATLAB Online 中打开

DON'T use input for the name of a variable because it's already the name of a function that asks the user for a variable. Call it userInput or something. What does this show in the command window

whos a

I'd like to know if the badly-named "a" is actually a gray scale image, an RGB image, or a character array (string).

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jana 2023-1-10

its now writtenas a =app.Image;

o=im2gray(a);

c=imhist(o);

I=imshow(c,'parent',app.UIAxes2,...

'XData',[1 app.UIAxes2.Position(3)],...

'YData',[1 app.UIAxes2.Position(4)]);

app.UIAxes2.XLim=[0 I.XData(2)];

app.UIAxes2.YLim=[0 I.YData(2)];

still nothing shows up

Image Analyst 2023-1-10

在 MATLAB Online 中打开

imshow() works on an image, not a histogram object or counts of pixels. Don't use imshow at all. If you want to see the histogram, just use imhist(o) by itself

imhist(o); % "o" is a horrible name for a variable!

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