What does the following code do?
显示 更早的评论
clear all
close all
clc
x= input('Enter initial condition: ')
eps= input('Enter accuracy : ')
Nmax= 1e5
for N=1:Nmax
f= 2*x+exp(x/pi)+sin(pi*x)-20
df= 2+(1/pi)*exp(x/pi)+pi*cos(pi*x)
newx= x-f/df
if abs(newx-x)<=eps
disp(['The solotion is: ',num2str(newx)])
disp(['The number of attempts is: ',num2str(N)])
break
end
x=newx
end
if N==Nmax
disp('There is no solution for the given conditions!')
end
3 个评论
John D'Errico
2022-12-26
Talk to the source of the code Asing what uncommented junk code does is difficult to say, especially if we are given no clue as to what it is supposed to do. And, sorry, but this is junk code.
the cyclist
2022-12-26
What your code will do is give the error message you see in red above (after I formatted your code, and ran it here).
daniel
2022-12-26
回答（1 个）
Voss
2022-12-26
0 个投票
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