How to solve this error? Invalid types for comparison.
1 次查看(过去 30 天)
显示 更早的评论
I want to calculate accuracy, sensitivity,...,etc based on actual and predicted data, this code is working well for numbered labels but it gives this error for string labels.
0 个评论
采纳的回答
Geoff Hayes
2022-12-30
@Bajdar Nouredine - for string labels, I suspect that you need to use strcmp rather than == for checking to see if two strings are identical (if that is what you mean). You would probably want to check the type (i.e. use isstring) first (of the ACTUAL and PREDICTED arrays) to determine whether you need to use strcmp or ==.
5 个评论
Geoff Hayes
2022-12-31
@Bajdar Nouredine - the ACTUAL and PREDICTED seem to be categorical arrays. I suppose you could convert to string arrays and then compare the two like
idx = strcmp(string(ACTUAL), string(PREDICTED)');
I had to transpose the PREDICTED array so that both it and ACTUAL are 288x1. idx should reference those elements/indices that match in both arrays.
更多回答(0 个)
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!