How to solve this error? Invalid types for comparison.
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I want to calculate accuracy, sensitivity,...,etc based on actual and predicted data, this code is working well for numbered labels but it gives this error for string labels.
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Geoff Hayes
2022-12-30
0 个投票
@Bajdar Nouredine - for string labels, I suspect that you need to use strcmp rather than == for checking to see if two strings are identical (if that is what you mean). You would probably want to check the type (i.e. use isstring) first (of the ACTUAL and PREDICTED arrays) to determine whether you need to use strcmp or ==.
5 个评论
Bajdar Nouredine
2022-12-30
Geoff Hayes
2022-12-30
@Bajdar Nouredine the error message is
Error using == (line 30)
Invalid types for comparison.
Error in Evaluate (line 10)
idx = (ACTUAL()==1);
which is due to the above line. When ACTUAL is all strings, what are you attempting to compare with this line of code? What should it be?
Bajdar Nouredine
2022-12-31
Geoff Hayes
2022-12-31
@Bajdar Nouredine - the ACTUAL and PREDICTED seem to be categorical arrays. I suppose you could convert to string arrays and then compare the two like
idx = strcmp(string(ACTUAL), string(PREDICTED)');
I had to transpose the PREDICTED array so that both it and ACTUAL are 288x1. idx should reference those elements/indices that match in both arrays.
Bajdar Nouredine
2023-1-3
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