select data from the row
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Hi colleagues...
i have data from txt file, i want to select data from the rows number 10,11,12
* NMEA Latitude = 22 09.66 N
* NMEA Longitude = 038 29.57 E
* NMEA UTC (Time) = Oct 11 2008 02:55:45
And delete this char
str= {'* NMEA Latitude =' , '* NMEA Longitude =', '* NMEA UTC (Time)='} ;
Then convert the remainder data to a value (vector)
Latitude= 22 09.
Longitude= 038 29.57
time= Oct 11 2008 02:55:45
采纳的回答
Mathieu NOE
2023-1-2
hello
as far as I understood, you want lat and long as numerical values , so I opted to convert from degress / minutes format to degrees only (30° 30' = 30.5°)
for the "time" data , I am not sure what you want to do, keep it as a string or transform it to date object ?
fileDir = pwd; % define your working directory
filename = 'oc449.txt';
D=readlines(fullfile(fileDir,filename)); % read as string array
idx1=find(contains(D,'NMEA Latitude')); % find the start lines index
idx2=find(contains(D,'NMEA UTC (Time)')); % find the stop lines index
D_extract = strtrim(D(idx1:idx2));
outdata = split(D_extract,'=');
Latitude = str2double(split(strtrim(outdata(1,2)),' ')) % deg / minutes / nan
Latitude = Latitude(1)+Latitude(2)/60; % converted to deg
Longitude = str2double(split(strtrim(outdata(2,2)),' ')) % deg / minutes / nan
Longitude = Longitude(1)+Longitude(2)/60; % converted to deg
Time = strtrim(outdata(3,2)); % time as string
% convert to datetime object
Time_date = datetime(Time,'InputFormat','MMM dd yyyy HH:mm:ss');
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