How to write a matlab code for this equation?
显示 更早的评论
回答（1 个）
Luca Ferro
2023-1-6
编辑：Luca Ferro
2023-1-6
0 个投票
Fi= @(I) ((2*(alpha*beta)^((alpha+beta)/2))/T(alpha)*T(beta))*(I^(alpha+beta))*K*2*sqrt(alpha*beta*I);
if you want to show alpha and beta as symbols in the workspace you can go for something like (see here):
alpha=evalin(symengine,'`α`');
Since you didn't specify anything i interpreted T as a function. You will need to define it as well.
4 个评论
John D'Errico
2023-1-6
编辑：John D'Errico
2023-1-6
I woud guess that K may also be a function, as putting parens around what follows makes little sense otherwise, and the sqrt(alpha*beta) term might have then been absorbed into a previous term. As well, the 2 would become a 4 in front of the entire expression, combining with the other 2. Even that sqrt(I) term could then be absorbed into a previous term.
For all of those reasons, I am pretty confident that K is in fact a function, unsupplied, but still a function.
Torsten
2023-1-6
... same for T.
Luca Ferro
2023-1-9
yeah you are definetly right about K, it is indeed a function for sure, i just didn't notice. This should be correct now:
Fi= @(I) ((2*(alpha*beta)^((alpha+beta)/2))/T(alpha)*T(beta))*(I^(alpha+beta))*K(2*sqrt(alpha*beta*I));
Walter Roberson
2023-1-9
编辑：Walter Roberson
2023-1-9
https://en.m.wikipedia.org/wiki/K-function ? Or is it https://www.mathworks.com/help/matlab/ref/besselk.html ?
类别
在 帮助中心 和 File Exchange 中查找有关 Data Type Identification 的更多信息
2023-1-5
2023-1-9
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
