bisection method using matlab

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Firdaus Rosli
Firdaus Rosli 2011-10-20
回答： Niranjan Sundararajan 2023-6-7
vertical velocity of a motorcycle due to a road bump is given by:
V(t)=X*exp(-zeta*Wn*t)*(-zeta*Wn*sin(Wd*t)+Wd*cos(Wd*t))
Where; X=maximum displacement of the motor cycle , 0.4550m zeta=damping constant , 0.4037 Wn=undamped natural frequency of the system , 3.4338rad/s Wd= Wn*sqrt(1-zeta^2)=damped natural frequency of the system t=time
Determine the time, t, at which the velocity of the motorcycle attains a value of 1m/s.
I know how to find it by using microsoft excel. However, I would like to try it in matlab. Can anyone help me?
Thx
  1 个评论
bym
bym 2011-10-21
you usually have to show some attempt at using matlab, and ask a specific question to get a response

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回答（1 个）

Niranjan Sundararajan
Ran in:
Hey there,
What you essentially want to compute is the inverse of the function V(t). To do so in MATLAB, you can use the fzero function. Documentation link - https://in.mathworks.com/help/matlab/ref/fzero.html
Now, you want to find V(inverse) of 1 m/s. To do so, follow the following code snippet. P.S. - I have used the formula you provided for velocity.
format long;
V=1; %m/s
f_inv_val_of_t = fzero(@(t) f(t) - V, 0) %seconds
f_inv_val_of_t =
0.103244252227968
verification_output = f(f_inv_val_of_t) % = 1 m/s only
verification_output =
1.000000000000000
function V = f(t)
%time in seconds
X = 0.4550; %m
zeta = 0.4037;
Wn = 3.4338; %rad/s
Wd = Wn*sqrt(1-zeta^2); %rad/s
V=X*exp(-zeta*Wn*t)*(-zeta*Wn*sin(Wd*t)+Wd*cos(Wd*t)); %m/s
end

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