FOR Loop Final Answer Problem
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Question gives us the vector increase which has the percentage increase for the fees of upcoming years and asks us to find the tuition fee after 4 years if current fee for a year is 5000
Exact Question:
My code is as below. It runs but final value is not correct.
sum = 5000;
increase = [10 8 10 16 15 4 6 7 8 10 8 12 14 15 8 7 6 5 7 8 9 8];
for x = increase(:,1):increase(:,3)
sum = (sum*(x/100)) + sum;
end
fprintf('%d', sum)
采纳的回答
Your code predicts a 4 year tuition of 5500. Clearly that is not correct. How would I solve this, even if I was not using a loop?
format short g
increase = [10 8 10 16 15 4 6 7 8 10 8 12 14 15 8 7 6 5 7 8 9 8];
tuition = 5000*cumprod(1 + [0,increase]/100)
That is the YEARLY tuition. If you want 4 years, then we could do this:
fouryeartuition = conv(tuition,[1 1 1 1],'valid')
And my guess is you were being asked to produce the total tuition, as if you started this year, or any year for the next 20 years.
plot(fouryeartuition,'o')
Anyway, 5500 is clearly not correct, although I think the question is far too vague to have a good answer. A good, well-posed question would have been explicit. Why do I think the request was to see a prediction of the total 4 year tuition over the next 20 years? Because they gave you 20 years of yearly tuition hikes as information!
Anway, why did your loop fail? LOOK AT WHAT YOU WROTE!
for x = increase(:,1):increase(:,3)
What is increase(:,1)? increase(:,3)
increase(:,1)
increase(:,3)
So what did your loop do? For example, try this:
for i = 10:10
i
end
Do you see the loop only runs for ONE iteration?
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