Could you please clarify what your expected output is?
In a function we need to input the first element of matrix?
1 次查看（过去 30 天）
显示 更早的评论
for say let the function be
function[d]=myFIRST(x,y)
for i=1:100
y(i+1)=x+y(i)
d=y;
end
end
myFIRST(1,2)
here y is iteratively changing and the first element is defined.
it doesnt read iteratively new values
4 个评论
Davide Masiello
2023-1-10
That's not the case for me, all the iterations are displayed.
myFIRST(1,2)
function[d]=myFIRST(x,y)
for i=1:100
y(i+1)=x+y(i)
d=y;
end
end
回答（1 个）
Mathieu NOE
2023-1-23
hello
simply this. personnay I don't like to use the same variable name in both iput and output of a function .
y = myFIRST(1,2)
function[y]=myFIRST(x,y)
for i=1:100
y(i+1)=x+y(i);
end
end
2 个评论
Stephen23
2023-1-23
"I don't like to use the same variable name in both iput and output of a function."
Dyuman Joshi
2023-1-23
编辑：Dyuman Joshi
2023-1-23
Thank you for the comment, @Stephen23. This was something I was looking for, but couldn't word it properly when I asked this question - Replacing Arrays and Matrices
Can you edit your answer on my question to include this info? So I can accept your answer.
另请参阅
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
您也可以从以下列表中选择网站：
美洲
- América Latina (Español)
- Canada (English)
- United States (English)
欧洲
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom (English)
亚太
- Australia (English)
- India (English)
- New Zealand (English)
- 中国
- 日本Japanese (日本語)
- 한국Korean (한국어)