Logical indexing returns different dimensions

a = [3, 2]
a = 1×2
3 2
b = [1; 1] == 1
b = 2×1 logical array
1 1
a(b) % returns a 1x2 array
ans = 1×2
3 2
a = [3, 2; 4, 5]
a = 2×2
3 2 4 5
b = [1; 1; 1; 1] == 1
b = 4×1 logical array
1 1 1 1
a(b) % returns a 4x1 array
ans = 4×1
3 4 2 5

1 个评论

I was expecting both to return 1 x n type arrays but that's not the case. Am I missing something?

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 采纳的回答

Vectors have different indexing behavior than matrices. There's nothing more to it, except perhaps to point out that it's not just logical indexing. It applies to regular indexing as well:
a=[10,20,30,40];
a([1;2])
ans = 1×2
10 20
a=[10,20;30 40];
a([1;2;3;4])
ans = 4×1
10 30 20 40

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