how to create a struct that would have number of fields that corresponds to the number of iterations inside a loop and also automatically save this data

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osasunmwen efosa 2023-1-13

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https://ww2.mathworks.cn/matlabcentral/answers/1893530-how-to-create-a-struct-that-would-have-number-of-fields-that-corresponds-to-the-number-of-iterations

评论： osasunmwen efosa 2023-1-13

for day = 1:7
    for i = 1:length(signal)
        for j = 1:36
            MPE1(i,j) = signal(i,j,day) - signal(i,j,day) - kE1 * (signal(i,j,day) - signal(i,j,day)); 
        end
    end
    MeanE1 = movmean(MPE1,3,'omitnan');
    zero_meanE1 = MPE1(:,PRN) - MeanE1(:,PRN); %% need to save this in struct for each day
end

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Stephen23 2023-1-13

"how to create a struct that would have number of fields that corresponds to the number of iterations..."

So many fields... complex.

Simpler: non-scalar structure, cell array, numeric array...

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Answer 1

Jan 2023-1-13

在 MATLAB Online 中打开

Result = struct();
for day = 1:7
    % No loop needed:
    MPE1   = signal(:, :, day) - signal(:, :, day) - kE1 * (signal(:, :, day) - signal(:, :, day)); 
    MeanE1 = movmean(MPE1, 3, 'omitnan');
    zero_meanE1 = MPE1(:,PRN) - MeanE1(:,PRN);
    Result(day).zmE1 = zero_meanE1;
    
    % Or:
    % Result.zmE1{day} = zero_meanE1;
end
save('Result.mat', 'Result');