清空筛选条件
清空筛选条件

so in appdesigner im building a list box to turn the image to (red ,blue ,green) this is my code for it bout it wont run

1 次查看（过去 30 天）
jana
jana 2023-1-13
编辑： Jan 2023-1-13
value = app.ListBox.Value;
if value== 'Red'
a=(app.Image);
red=a;
red(:,:,2:3)=0
setappdata(0,'filename',red);
setappdata(0,'imrotation',red);
I=imshow(red,'parent',app.UIAxes2,...
'XData',[1 app.UIAxes2.Position(3)],...
'YData',[1 app.UIAxes2.Position(4)]);
app.UIAxes2.XLim=[0 I.XData(2)];
app.UIAxes2.YLim=[0 I.YData(2)];
else if value== 'Blue'
Agray=im2gray(app.Image);
zerochan = zeros(size(Agray),class(Agray));
blue = cat(3,zerochan,zerochan,Agray);
setappdata(0,'filename', blue);
setappdata(0,'imrotation', blue);
I=imshow(blue,'parent',app.UIAxes2,...
'XData',[1 app.UIAxes2.Position(3)],...
'YData',[1 app.UIAxes2.Position(4)]);
app.UIAxes2.XLim=[0 I.XData(2)];
app.UIAxes2.YLim=[0 I.YData(2)];
else
Agray=im2gray(app.Image);
zerochan = zeros(size(Agray),class(Agray));
green = cat(3,zerochan,Agray,zerochan);
setappdata(0,'filename',green);
setappdata(0,'imrotation',green);
I=imshow(green,'parent',app.UIAxes2,...
'XData',[1 app.UIAxes2.Position(3)],...
'YData',[1 app.UIAxes2.Position(4)]);
app.UIAxes2.XLim=[0 I.XData(2)];
app.UIAxes2.YLim=[0 I.YData(2)];
end
end
end
  1 个评论
Jan
Jan 2023-1-13
编辑：Jan 2023-1-13
Please do not post code as screenshots, but as text. Then it can be used to create an answer with copy&paste.
This is not twitter: No # before the tags. Thanks.

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Kevin Holly
Kevin Holly 2023-1-13
Based on the red squiggly line under Methods in your screenshot, you may have an extra "end" in your code.
  2 个评论
Kevin Holly
Kevin Holly 2023-1-13
Ran in:
Use strings instead of character arrays for your if conditions
if value == "Red"
The size was causing issues. See difference of size between character and string arrays below.
Character array:
size('Red')
ans = 1×2
1 3
String array:
size("Red")
ans = 1×2
1 1

请先登录，再进行评论。

类别

在 Help Center 和 File Exchange 中查找有关 Develop Apps Using App Designer 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by