Getting Error while using Transparency to object (alpha)

3 次查看（过去 30 天）
Telema Harry
Telema Harry 2023-1-13
评论： Telema Harry 2023-1-14
Ran in:
I get the following error ("Unable to use a value of type matlab.graphics.chart.primitive. Surface as an index. alpha(s,.2)") message sometimes and I don't know why?
r = 50; % The radius of the circular plan given in Km
r = km2deg(r); % Convert to Degree
[X,Y,Z] = cylinder(r);
p0=[48,278,0]; % base location in Degrees
X=X+p0(1); Y=Y+p0(2); Z=Z+p0(3); %translate cylinder to new location
h = 80;
Z = Z*h;
subplot(2, 2, [1 3])
s = surf(Y,X,Z,'FaceColor','#80B3FF', 'EdgeColor','none');
% view(43,180);
% camdolly(0,0,0)
alpha(s,.2)
I am using MATLAB R2022a on a macOS ventura 13.1 machine.

请先登录，再回答此问题。

采纳的回答

Voss
Voss 2023-1-14
编辑：Voss 2023-1-14
You have a variable called "alpha" in your workspace, which is preventing you from running the "alpha" function.
You should remove the variable by running the command
clear alpha
on the command line, and then run your script again.

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Lighting, Transparency, and Shading 的更多信息

标签

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by