How to find the maximum value of the power and its position on the time axis (x,y)?

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Need your help guys !
Need to find the max and the min of p , shown as [x,y].

回答(1 个)

Torsten
Torsten 2023-1-15
编辑:Torsten 2023-1-15
s=1.25;
t1=0:0.01:pi/2;
t2=pi/2:0.01:pi;
t=[t1 t2];
p1= 4*(sin(2*t1)).^2.*exp(-t1/s).^2 + 2;
p2= 4*(sin(2*t2)).^2.*exp(-t2/s) + 2;
[~,i1_min] = min(p1);
[~,i1_max] = max(p1);
[~,i2_min] = min(p2);
[~,i2_max] = max(p2);
figure()
hold on
plot([t1 t2],[p1 p2])
plot(t1(i1_min),p1(i1_min),'o',"Color","r")
plot(t1(i1_max),p1(i1_max),'o',"Color","r")
plot(t2(i2_min),p2(i2_min),'o',"Color","r")
plot(t2(i2_max),p2(i2_max),'o',"Color","r")
hold off
  2 个评论
Image Analyst
Image Analyst 2023-1-27
If this Answer solves your original question, then could you please click the "Accept this answer" link to award the answerer with "reputation points" for their efforts in helping you? They'd appreciate it. Thanks in advance. 🙂 Note: you can only accept one answer (so pick the best one) but you can click the "Vote" icon for as many Answers as you want. Voting for an answer will also award reputation points.
By the way, you might look at findpeaks

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