How to find the maximum value of the power and its position on the time axis (x,y)?

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David 2023-1-15

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https://ww2.mathworks.cn/matlabcentral/answers/1894315-how-to-find-the-maximum-value-of-the-power-and-its-position-on-the-time-axis-x-y

评论： Image Analyst 2023-1-27

Need your help guys !

Need to find the max and the min of p , shown as [x,y].

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Answer 1

Torsten 2023-1-15

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1894315-how-to-find-the-maximum-value-of-the-power-and-its-position-on-the-time-axis-x-y#answer_1149015

编辑：Torsten 2023-1-15

在 MATLAB Online 中打开

s=1.25;

t1=0:0.01:pi/2;

t2=pi/2:0.01:pi;

t=[t1 t2];

p1= 4*(sin(2*t1)).^2.*exp(-t1/s).^2 + 2;

p2= 4*(sin(2*t2)).^2.*exp(-t2/s) + 2;

[~,i1_min] = min(p1);

[~,i1_max] = max(p1);

[~,i2_min] = min(p2);

[~,i2_max] = max(p2);

figure()

hold on

plot([t1 t2],[p1 p2])

plot(t1(i1_min),p1(i1_min),'o',"Color","r")

plot(t1(i1_max),p1(i1_max),'o',"Color","r")

plot(t2(i2_min),p2(i2_min),'o',"Color","r")

plot(t2(i2_max),p2(i2_max),'o',"Color","r")

hold off

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David 2023-1-15

Thank you !

appreciate it !

Image Analyst 2023-1-27

If this Answer solves your original question, then could you please click the "Accept this answer" link to award the answerer with "reputation points" for their efforts in helping you? They'd appreciate it. Thanks in advance. 🙂 Note: you can only accept one answer (so pick the best one) but you can click the "Vote" icon for as many Answers as you want. Voting for an answer will also award reputation points.

By the way, you might look at findpeaks

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