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mohamed saber
mohamed saber 2011-10-21
评论： Mohammed Anveez 2020-5-16
i've a problem in this code ... there isn't any output graph .. i don't know why ???
for t=0:.00001:1;
n=n+1;
x1=2.5*cosd(10*pi*t);
x2=2*cosd(8*pi*t);
x1(n)=x1;
x2(n)=x2;
end
plot(t,x1)
hold on
plot(t,x2)
  1 个评论
Jan
Jan 2011-10-21
Please use code formatting as explained in the "Markup help" link.

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采纳的回答

Robert Cumming
Robert Cumming 2011-10-21
your plotting your vector x1 against a scalar value of t.
Change your code to:
figure
plot([0:.00001:1],x1)
hold on
plot([0:.00001:1],x2)
  2 个评论
Jan
Jan 2011-10-21
Adding unnecessary square brackets around a vector wastes time. "0:00001:1" is a vector already.
Robert Cumming
Robert Cumming 2011-10-21
True - they are unnecesary...
Do you mean computational time or typing time?
I originally started doing it as I (personally) think its more readable...
Now I do it without thinking about it - maybe its a bad habit - but they are the hardest to break... ;)

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更多回答（5 个）

Andrei Bobrov
Andrei Bobrov 2011-10-21
t=0:.00001:1;
plot(t,2.5*cosd(10*pi*t))
hold on
plot(t,2*cosd(8*pi*t))
or
plot(t,[2.5*cosd(10*pi*t),2*cosd(8*pi*t)])
  1 个评论
Mohammed Anveez
Mohammed Anveez 2020-5-16
even iam facing same issue in plotting

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mohamed saber
mohamed saber 2011-10-21
thanks to all
AR
AR 2017-3-21
How can I plot the my Liklihood function for a large n, say at 100, to show max? fplot did not work.
L_theta=1/16*((1+x1*theta)*(1+x2*theta)*(1+x3*theta)*(1+x4*theta))
fplot(L_theta,[-1,1])
I used the iterative Newton method to solve via convergence to theta_MLE and would like to graphically display this as well.
Anyone have a suggestion?
Thank you.
Pawello85
Pawello85 2018-11-6
Hello. I have a small problem to generate a higher resolution plot.
fs=1000; t=0.075:1/fs:0.225; fi=0; A=0.5; f=10:190/150:200; w=2*pi*f; x=A*cos(w.*t+fi); figure plot(t,x); xlabel('t [s]'); ylabel('Amplitude');
carlos ruiz
carlos ruiz 2019-12-1
Hello i have s problem with this code i can not plot very well this vector
clc
clear
syms L real
T=[5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25]';%Periodos segundos
d=[5 10 30 50 80 100 200 1000 2000];%Tirante de agua profundidad
w=(2*pi./T).^2;
g=9.81;
for i=1:21
for d=1:9
K=2*pi/L;
f=g*(K)*tanh(K*d(1))-w(i);
Ls(i)=solve(f,'L')
Lss=eval(Ls')
end
end
y=abs(Lss)
grid on
hold on
plot(T,y,'r');
xlabel('Wave period T (sec)'); %Titulo del eje X
ylabel('Wave length'); %Titulo del eje Y
title('The dispersion relationship gives the relationship between wave period and wave length For linear waves in finite water depth d'); %Titulo del gráfico

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