Create a row vector comparing strings in a for loop

I have two string arrays with different sizes and assume that the second one (s2) has a variable size.
I need to create a vector (index) that contains only the indices where 'strcmpi' returns the logical value 1. It works if 's2' contains only strings present in 's1', otherwiswe the following error occurs. I think that's because I am assigning to 'index' the size of 'k' but there will be only 3 logical value = 1, but I don't know how to fix it.
Any help would be appreciated. Thanks.
s1 = { 'FMO1','FMO2','FMO3','FMO4', 'BAO1', 'BAO2', 'BAO3', 'BAO4'};
s2 = {'mean','FMO1','BAO4','FMO2'};
for k = 1 : length(s2)
compare = strcmpi(s2{k},s1);
index(k) = find(compare==1)
end
Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.

1 个评论

Also thanks to you, do I have to accept your answer too? even if I already accepted the previous one

请先登录,再进行评论。

 采纳的回答

index = [];
s1 = { 'FMO1','FMO2','FMO3','FMO4', 'BAO1', 'BAO2', 'BAO3', 'BAO4'};
s2 = {'mean','FMO1','BAO4','FMO2'};
for k = 1 : length(s2)
compare = strcmpi(s2{k},s1);
index = [index,find(compare==1)];
end
index
index = 1×3
1 8 2
This way, even if any of the entry in s2 appears several times in s1 you should be ok.

更多回答(1 个)

The simple MATLAB approach:
s1 = { 'FMO1','FMO2','FMO3','FMO4', 'BAO1', 'BAO2', 'BAO3', 'BAO4'};
s2 = {'mean','FMO1','BAO4','FMO2'};
X = contains(s1,s2)
X = 1×8 logical array
1 1 0 0 0 0 0 1
Y = find(X) % optional
Y = 1×3
1 2 8

1 个评论

Thank you, I would accept your answer but I don't think I can accept more than one.

请先登录,再进行评论。

类别

帮助中心File Exchange 中查找有关 Logical 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by