How do I print a legend using a character array and integer array?

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Shelley Snider
Shelley Snider 2023-1-18
评论： Fangjun Jiang 2023-1-19
I want to print a legend that looks like this:
1st entry: 'Current solution, 4800 m DR'
2nd entry: 'Current solution, 7000 m DR'
3rd entry: 'Current solution, 9000 m DR'
4th entry: 'Archive solution, 4800 m DR'
5th entry: 'Archive solution, 7000 m DR'
6th entry: 'Archive solution, 9000 m DR'
The numbers come from a structure array. I'm trying to use sprintf, but I'm having troubles with the format of the 'Current' and 'Archive' strings. A character array does not work since sprintf iterates through each character instead of each word. Do I need to do a cell array and then do a comma separated list for that?
  1 个评论
Walter Roberson
Walter Roberson 2023-1-19
Ran in:
A character array does not work since sprintf iterates through each character instead of each word.
A = 'Current'
A = 'Current'
sprintf('->%s<-', A)
ans = '->Current<-'
sprintf('->%c<-', A)
ans = '->C<-->u<-->r<-->r<-->e<-->n<-->t<-'
You were using the wrong format item.

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采纳的回答

Stephen23
Stephen23 2023-1-19
Ran in:
COMPOSE() is perfect for this, but was first introduced in R2016b. You could use ARRAYFUN() or CELLFUN():
C = {'Current','Current','Current','Archive','Archive','Archive'};
V = [4800,7000,9000,4800,7000,9000];
fnh = @(t,n)sprintf('%s solution, %d m DR',t,n);
lgd = cellfun(fnh,C(:),num2cell(V(:)), 'uni',0)
lgd = 6×1 cell array
{'Current solution, 4800 m DR'} {'Current solution, 7000 m DR'} {'Current solution, 9000 m DR'} {'Archive solution, 4800 m DR'} {'Archive solution, 7000 m DR'} {'Archive solution, 9000 m DR'}

更多回答（1 个）

Fangjun Jiang
Fangjun Jiang 2023-1-18
编辑：Fangjun Jiang 2023-1-18
Ran in:
a="current";
b={'archive'};
c='current';
sprintf('%s',a)
ans = 'current'
sprintf('%s',b{1})
ans = 'archive'
sprintf('%s',c)
ans = 'current'
  2 个评论
Fangjun Jiang
Fangjun Jiang 2023-1-19
Ran in:
Use a for-loop, or use the cellfun() that @Stephen23 demonstrated.
Another trick is below, if you put the data in the right format
data={'1st','2nd','3rd';'Current','Archive','Current';4800,7000,9000};
sprintf('%s entry: ''%s solution, %d m DR''\n',data{:})
ans =
'1st entry: 'Current solution, 4800 m DR' 2nd entry: 'Archive solution, 7000 m DR' 3rd entry: 'Current solution, 9000 m DR' '

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