How do I take my generated string outputs from for loop and return a list?

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seq = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA'
for i=1:3:numel(seq)-2
a = (seq(i:i+2))
end
a = 'ACA'
a = 'UUU'
a = 'GCU'
a = 'GAC'
etc...
% Desired output --> ['ACA', 'UUU', 'GCU', 'GAC' ...]

采纳的回答

Walter Roberson
Walter Roberson 2023-1-19
You should be careful what you ask for. 'ACA' is the 1 x 3 char vector ['A' 'C' 'A'] and ['ACA' 'UUU'] is concatenating two 1 x 3 vectors together getting a 1 x 6 vector 'ACAUUU' -- back to where you started
seq = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA'
seq = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA'
a1 = [];
a2 = cell(0);
for i=1:3:numel(seq)-2
a1 = [a1, seq(i:i+2)];
a2{end+1} = seq(i:i+2);
end
a1
a1 = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA'
a2
a2 = 1×16 cell array
{'ACA'} {'UUU'} {'GCU'} {'UCU'} {'GAC'} {'ACA'} {'ACU'} {'GUG'} {'UUC'} {'ACU'} {'AGC'} {'AAC'} {'CUC'} {'AAA'} {'CAG'} {'ACA'}
a3 = reshape(seq, 3, []).'
a3 = 16×3 char array
'ACA' 'UUU' 'GCU' 'UCU' 'GAC' 'ACA' 'ACU' 'GUG' 'UUC' 'ACU' 'AGC' 'AAC' 'CUC' 'AAA' 'CAG' 'ACA'
I would suggest to you that the a3 method is easiest. You might want to cellstr() or string() the resutling 16x3 array.

更多回答(1 个)

Sulaymon Eshkabilov
Here si the solution:
a=[];
seq = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA'
seq = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA'
for i=1:3:numel(seq)-2
a = [a; (seq(i:i+2))];
end
a
a = 16×3 char array
'ACA' 'UUU' 'GCU' 'UCU' 'GAC' 'ACA' 'ACU' 'GUG' 'UUC' 'ACU' 'AGC' 'AAC' 'CUC' 'AAA' 'CAG' 'ACA'
  1 个评论
Stephen23
Stephen23 2023-1-19
编辑:Stephen23 2023-1-19
It is inefficient to keep expanding an array in a loop like that.
Simpler and much more efficient:
seq = 'ACAUUUGCUUCUGACACAACUGUGUUCACUAGCAACCUCAAACAGACA';
mat = reshape(seq,3,[]).'
mat = 16×3 char array
'ACA' 'UUU' 'GCU' 'UCU' 'GAC' 'ACA' 'ACU' 'GUG' 'UUC' 'ACU' 'AGC' 'AAC' 'CUC' 'AAA' 'CAG' 'ACA'

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