how to use a variable defined in one if loop in another loop also in matlab

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Imaad Aslam 2023-1-21

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https://ww2.mathworks.cn/matlabcentral/answers/1898100-how-to-use-a-variable-defined-in-one-if-loop-in-another-loop-also-in-matlab

评论： Stephen23 2023-1-21

if strcmpi(end_condt, '1')
    D  = l/10;
    depth = D - clr_cover - 5;
end
suprt_condtn = input('Is the Span (1) C/C Distance or (2)Clear Span = ');
suprt_lngth = input('What is the length of suport (in mm) ; ');
if strcmpi(suprt_condtn, '1')
    eff_span = min(l , ((l - suprt_lngth) + depth));
elseif strcmpi(suprt_condtn, '2')
   eff_span = min((l + suprt_lngth) , (l + depth));
else
    isempty(suprt_condtn)
        eff_span = min(l , ((l - suprt_lngth) + depth)); 
end
Here it says "Undefined function or variable 'depth'"

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Vilém Frynta 2023-1-21

It would be helpful to see the rest of your code. It appears to me that you have depth defined inside a if statement, where your conditions might not be met. It might be possible that your variable called end_condt is not a string (but a double or else), which would lead to logical 0.

Stephen23 2023-1-21

在 MATLAB Online 中打开

The numeric 1 is not equal to the text '1', Lets check right now:

strcmpi(1,'1')
ans = logical
   0

Yet your code is written on the assumption that is true. But in fact, MATLAB does not implicitly convert text to the numeric values that it might happen to contain. Or not.

Solution: store numeric values as numeric. And then compare them as numeric.

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