Hoe can I convert my script to a function?

2023 1 22
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更新时间：2023 1 22
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Hi all,
I coded an script. I want to convert it to fuction so that I can call it whereever it is needed. Could you please guide me how to do that correctly? The inputs of the fuction are Alpha and Mu, and the output is supposed to be lambda.
clear
close all
clc
load("Coefficient.mat")
Alpha=2;
Mu=[0.2 0.4 0.8];
Alpha_vector=Coefficient(:,2)+Coefficient(:,3).*Mu+Coefficient(:,4).*(Mu.^2)+Coefficient(:,5).*(Mu.^3)+Coefficient(:,6).*(Mu.^4)...
+Coefficient(:,7).*(Mu.^5)+Coefficient(:,8).*(Mu.^6);
Mu_max=[10 10 10 10 10 9 8 sqrt(42) sqrt(30) 5 sqrt(20) sqrt(12) 3 sqrt(6) 2.1040 1.6818 1.4142 0.9487 0.7483 0.6...
0.4472 0.4 0.3464 0.27 0.22 0.1414];
lambda_min=[0.57 0.46 0.4 0.35 0.32 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3];
lambda=zeros(1,length(Mu));
for t=1:length(lambda)
if Alpha>8 && Mu(t)>=Mu_max(26)
lambda(t)=lambda_min(26);
elseif Alpha>8 && Mu(t)<Mu_max(26)
lambda(t)=Alpha_vector(26,t);
else
for k=1:length(Coefficient(:,1))
if ismembertol(Alpha, Coefficient(k,1), 1e-8) && Mu(t)>=Mu_max(k)
lambda(t)=lambda_min(k);
elseif ismembertol(Alpha, Coefficient(k,1), 1e-8) && Mu(t)<Mu_max(k)
lambda(t)=Alpha_vector(k,t);
elseif Alpha>Coefficient(k,1) && Alpha<Coefficient(k+1,1) && Mu(t)>=Mu_max(k)
lambda(t)=lambda_min(k);
elseif Alpha>Coefficient(k,1) && Alpha<Coefficient(k+1,1) && Mu(t)<Mu_max(k)
lambda(t)=interp1([0:0.1:1, 1.2:0.2:2, 2.5:0.5:6, 7, 8], Alpha_vector(:,t), Alpha);
end
end
end
end

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 采纳的回答

Torsten
Torsten 2023-1-22
编辑：Torsten 2023-1-22

0 个投票

If the coefficients don't change in the course of the simulation, you should read "Coefficient.mat" only once and pass the matrix to "fun" together with "Alpha" and "Mu".
function lambda = fun(Alpha,Mu,Coefficient)
% Insert your script
end

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