Hoe can I convert my script to a function?

4 次查看(过去 30 天)
Hi all,
I coded an script. I want to convert it to fuction so that I can call it whereever it is needed. Could you please guide me how to do that correctly? The inputs of the fuction are Alpha and Mu, and the output is supposed to be lambda.
clear
close all
clc
load("Coefficient.mat")
Alpha=2;
Mu=[0.2 0.4 0.8];
Alpha_vector=Coefficient(:,2)+Coefficient(:,3).*Mu+Coefficient(:,4).*(Mu.^2)+Coefficient(:,5).*(Mu.^3)+Coefficient(:,6).*(Mu.^4)...
+Coefficient(:,7).*(Mu.^5)+Coefficient(:,8).*(Mu.^6);
Mu_max=[10 10 10 10 10 9 8 sqrt(42) sqrt(30) 5 sqrt(20) sqrt(12) 3 sqrt(6) 2.1040 1.6818 1.4142 0.9487 0.7483 0.6...
0.4472 0.4 0.3464 0.27 0.22 0.1414];
lambda_min=[0.57 0.46 0.4 0.35 0.32 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3 0.3];
lambda=zeros(1,length(Mu));
for t=1:length(lambda)
if Alpha>8 && Mu(t)>=Mu_max(26)
lambda(t)=lambda_min(26);
elseif Alpha>8 && Mu(t)<Mu_max(26)
lambda(t)=Alpha_vector(26,t);
else
for k=1:length(Coefficient(:,1))
if ismembertol(Alpha, Coefficient(k,1), 1e-8) && Mu(t)>=Mu_max(k)
lambda(t)=lambda_min(k);
elseif ismembertol(Alpha, Coefficient(k,1), 1e-8) && Mu(t)<Mu_max(k)
lambda(t)=Alpha_vector(k,t);
elseif Alpha>Coefficient(k,1) && Alpha<Coefficient(k+1,1) && Mu(t)>=Mu_max(k)
lambda(t)=lambda_min(k);
elseif Alpha>Coefficient(k,1) && Alpha<Coefficient(k+1,1) && Mu(t)<Mu_max(k)
lambda(t)=interp1([0:0.1:1, 1.2:0.2:2, 2.5:0.5:6, 7, 8], Alpha_vector(:,t), Alpha);
end
end
end
end

采纳的回答

Torsten
Torsten 2023-1-22
编辑:Torsten 2023-1-22
If the coefficients don't change in the course of the simulation, you should read "Coefficient.mat" only once and pass the matrix to "fun" together with "Alpha" and "Mu".
function lambda = fun(Alpha,Mu,Coefficient)
% Insert your script
end
  4 个评论

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Entering Commands 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by