Not enough input arguments (line 2)
显示 更早的评论
Using the two functions I have defined so far (nonsense and printstuff) to run the for loop at the end. When running the for loop, it turns me back to the nonsense .m file and says 'not enough input arguments' (line2). Can anyone help with this?
NONSENSE:
function y=nonsense(x)
if mod(x,2) == 0
disp(x^2);
else
disp(0);
end
end
PRINTSTUFF:
function printstuff(func,values)
fprintf('Function evaluated at %d points: \n',length(values))
for q = 1:length(values)
fprintf('point %0.6f has value %0.6f\n',values(q),func(values(q)))
end
end
FOR LOOP:
printstuff(nonsense,[4 11 15 20])
for x = [4 11 15 20]
nonsense(x);
end
1 个评论
The function NONSENSE requires one input argument when it is called.
Here you are calling NONSENSE with zero input arguments:
printstuff(nonsense,[4 11 15 20])
% ^^^^^^^^ calling with zero input arguments.
What do you expect that to achieve? It seems that you need to use a function handle.
采纳的回答
You need to learn about function handles:
I also had to fix your code because you had not defined the output argument "y" inside NONSENSE().
% v !!! define function handle !!!
printstuff(@nonsense,[4,11,15,20])
function y = nonsense(x)
if mod(x,2) == 0
y = x^2;
else
y = 0;
end
end
function printstuff(func,values)
fprintf('Function evaluated at %d points: \n',length(values))
for q = 1:length(values)
fprintf('point %0.6f has value %0.6f\n',values(q),func(values(q)))
end
end
更多回答（1 个）
x=12:10:42;
out=nonsense(x);
function y=nonsense(x)
if mod(x,2) == 0
y=x.^2;
else
y=0;
end
disp(y)
end
2 个评论
meman4567
2023-1-24
You can do it with a single function.
x = [4 11 15 20];
% x=[4 8 12 16 20];
out=nonsense(x);
function y=nonsense(x)
fprintf('Function evaluated at %d points: \n',length(x))
for i=1:length(x)
if mod(x(i),2) == 0
y=x(i).^2;
fprintf('point %0.6f has value %0.6f\n',x(i),y)
else
y=0;
fprintf('point %0.6f has no value %0.6f\n',x(i),y)
end
end
end
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