I am using MATLAB function block for linprog as follows but this error occurred-Size mismatch for MATLAB expression 'linprog'. Expected = 1x1 Actual = 2x1

7 次查看（过去 30 天）
gurparas singh
gurparas singh 2023-1-24
回答： Tejas 2024-11-14，6:35
function s1 = fcn(Iref,Ib)
%#codegen
coder.extrinsic('linprog');
s1=zeros();
A = [0 0;0 0];
b = [0 0];
Aeq = [0 0];
beq = 0;
lb = [-5,-5];
ub = [5,5];
f = [Iref -Ib];
%Solve the linear program.
[s1] = linprog(f,A,b,Aeq,beq,lb,ub);
end

请先登录，再回答此问题。

回答（1 个）

Tejas
Tejas 2024-11-14，6:35
Hello Gurparas,
The error indicates that the MATLAB Function block expects the output variable to be 1x1 in size, but the 'linprog' function actually returns a 2x1 output. This mismatch is causing the issue.
The problem arises because the output variable 's1' was initially set to a size of 1x1.
s1=zeros();
In a MATLAB Function block, a variable can only change size during simulation if the 'Support variable-size array' block property is enabled. For more details, you can refer to this documentation:
web(fullfile(docroot, 'simulink/ug/declare-variable-size-inputs-and-outputs.html'));
To fix this issue, set the size of the output variable 's1' to 2x1 beforehand.
s1=zeros(2,1);

类别

在 Help Center 和 File Exchange 中查找有关 Solver Outputs and Iterative Display 的更多信息

标签

产品


版本

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by