Unexpected output from simplify()
显示 更早的评论
I have this code, looking for the derivative of this equation
syms mp dv vc c
expr2 = (1-((c^2)/(vc^2))*(exp(dv/c)-1))/(exp(dv/c))==mp;
simplify(diff(expr2,c))
I am expecting just a simple expression, but the output contains an extra item
c^2*dv - 2*c^3*exp(dv/c) + dv*vc^2 + 2*c^3 == 0 & vc ~= 0
What does the thing after the & sign mean? Why is it here?
采纳的回答
Askic V
2023-1-25
It is probably because you he a division by vc in your expression.
.../(vc^2)...
This means simplified expression is valid only if vc is different than zero.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Symbolic Math Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
