Logical operator not evaluating correctly

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Andrew
Andrew 2023-1-26
回答： Star Strider 2023-1-26
Given the provided array X, create an array Y that is:
equal to 0 if the corresponding element of X is between -5 and +5, inclusive
equal to -1 if the corresponding element of X is less than -5
equalt to +1 if the corresponding element of X is greater than 5
Here is what I have:
Y = (~(X >= -5 & X <= 5) | (-1*(X < -5)) | (X>5)).
Why is the X < -5 not evaluationg to -1?

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采纳的回答

Star Strider
Star Strider 2023-1-26
Ran in:
Only two comparisons are actually required here —
X = linspace(-7, 7, 15);
Y = -(X < -5) + (X > 5);
Check_Result = [X; Y]
Check_Result = 2×15
-7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 -1 -1 0 0 0 0 0 0 0 0 0 0 0 1 1
.

更多回答（2 个）

Walter Roberson
Walter Roberson 2023-1-26
A|B is an or test and returns a logical value -1 is nonzero which is considered true, and since you or everything together you are going to end up with logical true for those entries.
Try adding the results of the computation
Les Beckham
Les Beckham 2023-1-26
Ran in:
I would do this in separate steps.
X = randi([-20, 20], [1 15])
X = 1×15
3 -6 2 6 -7 -8 -7 13 17 -3 5 -13 -17 5 -1
Y = zeros(size(X));
Y(X < -5) = -1;
Y(X > 5) = 1
Y = 1×15
0 -1 0 1 -1 -1 -1 1 1 0 0 -1 -1 0 0

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