Finding a redundant pattern in a matrix
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Hi,
I'm trying to compare a serie of number in a matrix of cells to see if some pattern are redondant.
The issue is that the pattern needs to be in the same order but it can be broken by another number.
For example : C1=[ 5 9 3]; C2=[ 9 5 3]; C3=[9 5 9 3]; C4=[5 9 8 3]; ...
In this case, I want to know that the pattern in C1 is repeated in C3 and C4 ... then do the same for C2.
Thanks for your help
Anna
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Image Analyst
2023-1-26
编辑：Image Analyst
2023-1-26
What's the use case (context as to why that is needed)? Have you tried a brute force search via a nested for loop? That would be pretty simple and fast for short vectors.
采纳的回答
C1=[ 5 9 3]; C2=[ 9 5 3]; C3=[9 5 9 3]; C4=[5 9 8 3]; C5 = [5 3 9 8];
is_in(C1, C2)
is_in(C1, C3)
is_in(C1, C4)
is_in(C1, C5)
function match = is_in(looking_for, in_what)
match = all(any(triu(looking_for.' == in_what),2));
end
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