Convert uint8 vector to float
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Hi All,
i have a .mf4-measurement data in uint8:
1×20 uint8 row vector
132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215
is there a way to convert it to these physical values (float)?
0.01 0.01 0.01 0.01 0.01 0.01 0.02 0.02 0.02 0.02 0.03 0.07 0.39 0.83 0.91 0.95 0.93 0.85 0.84 0.84
Thank u and kind regards,
2 个评论
Normally this would be as simple as converting the input data to double and multiplying by a scale factor. Your example values, however don't have a simple linear relationship between the input data and the example output data (see below).
Can you clarify how your example "physical values" were generated?
in = uint8([132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215])
out = [0.01 0.01 0.01 0.01 0.01 0.01 0.02 0.02 0.02 0.02 0.03 0.07 0.39 0.83 0.91 0.95 0.93 0.85 0.84 0.84]
SF = out./double(in)
plot(SF)
grid on
采纳的回答
Since you apparently know the mapping, one option is to simply calculate a linear regression (assuming that a linear relation exists) —
u = uint8([132 132 132 132 132 132 133 133 133 133 134 138 170 214 222 226 224 216 215 215]);
v = [0.01 0.01 0.01 0.01 0.01 0.01 0.02 0.02 0.02 0.02 0.03 0.07 0.39 0.83 0.91 0.95 0.93 0.85 0.84 0.84];
B = [132 1; 226 1] \ [0.01; 0.95] % Linear Regression
f = [double(u(:)) ones(size(u(:)))] * B;
figure
plot(double(u), v, '.', 'DisplayName','Data')
hold on
plot(double(u), f, '-', 'DisplayName','Linear Regression')
hold off
grid
xlabel('u')
ylabel('f')
legend('Location','N')
It would likely help to know what the data represent and what the actual conversion is. This approach is a guess that may not work on data other than those in the range of the ‘u’ vector.
.
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