How to select fields of a struct that contains certain string?

load table
selected = [];
for ii = 1:numel(trial_table)
    msg = {trial_table(ii).trial.message};
    idx = strcmp(msg,'1');
    selected = [selected trial_table(ii).trial(idx)];
end
disp(selected);
  1×150 struct array with fields:

    message
    time
    code
    reltime
    pvel

5 个评论
显示 3更早的评论隐藏 3更早的评论

Voss 2023-2-7

在 MATLAB Online 中打开

table.mat

Something like this?

load table
selected_trial_idx = [];
for ii = 1:numel(trial_table)
    msg = {trial_table(ii).trial.message};
    idx = strcmp(msg,'1');
    if any(idx)
        selected_trial_idx(end+1) = ii;
    end
end
selected = {trial_table(selected_trial_idx).trial};
disp(selected);
  Columns 1 through 11

    {1×133 struct}    {1×90 struct}    {1×66 struct}    {1×78 struct}    {1×72 struct}    {1×74 struct}    {1×83 struct}    {1×78 struct}    {1×64 struct}    {1×75 struct}    {1×66 struct}

  Columns 12 through 22

    {1×74 struct}    {1×72 struct}    {1×72 struct}    {1×83 struct}    {1×84 struct}    {1×88 struct}    {1×78 struct}    {1×82 struct}    {1×85 struct}    {1×84 struct}    {1×82 struct}

  Columns 23 through 33

    {1×88 struct}    {1×90 struct}    {1×80 struct}    {1×56 struct}    {1×76 struct}    {1×72 struct}    {1×75 struct}    {1×78 struct}    {1×105 struct}    {1×80 struct}    {1×74 struct}

  Columns 34 through 44

    {1×78 struct}    {1×66 struct}    {1×80 struct}    {1×70 struct}    {1×71 struct}    {1×62 struct}    {1×80 struct}    {1×68 struct}    {1×78 struct}    {1×70 struct}    {1×73 struct}

  Columns 45 through 55

    {1×71 struct}    {1×68 struct}    {1×82 struct}    {1×74 struct}    {1×74 struct}    {1×82 struct}    {1×67 struct}    {1×67 struct}    {1×72 struct}    {1×61 struct}    {1×78 struct}

  Columns 56 through 66

    {1×79 struct}    {1×90 struct}    {1×56 struct}    {1×85 struct}    {1×72 struct}    {1×67 struct}    {1×71 struct}    {1×59 struct}    {1×57 struct}    {1×80 struct}    {1×69 struct}

  Columns 67 through 77

    {1×80 struct}    {1×74 struct}    {1×72 struct}    {1×58 struct}    {1×67 struct}    {1×73 struct}    {1×58 struct}    {1×72 struct}    {1×60 struct}    {1×77 struct}    {1×72 struct}

  Columns 78 through 88

    {1×67 struct}    {1×77 struct}    {1×62 struct}    {1×79 struct}    {1×76 struct}    {1×70 struct}    {1×71 struct}    {1×75 struct}    {1×76 struct}    {1×69 struct}    {1×79 struct}

  Columns 89 through 99

    {1×82 struct}    {1×76 struct}    {1×59 struct}    {1×72 struct}    {1×78 struct}    {1×72 struct}    {1×74 struct}    {1×62 struct}    {1×73 struct}    {1×80 struct}    {1×72 struct}

  Columns 100 through 110

    {1×76 struct}    {1×74 struct}    {1×75 struct}    {1×78 struct}    {1×82 struct}    {1×77 struct}    {1×86 struct}    {1×73 struct}    {1×80 struct}    {1×82 struct}    {1×79 struct}

  Columns 111 through 121

    {1×75 struct}    {1×60 struct}    {1×66 struct}    {1×79 struct}    {1×68 struct}    {1×86 struct}    {1×82 struct}    {1×65 struct}    {1×80 struct}    {1×77 struct}    {1×73 struct}

  Columns 122 through 132

    {1×72 struct}    {1×67 struct}    {1×68 struct}    {1×76 struct}    {1×80 struct}    {1×70 struct}    {1×71 struct}    {1×80 struct}    {1×65 struct}    {1×84 struct}    {1×83 struct}

  Columns 133 through 143

    {1×70 struct}    {1×66 struct}    {1×81 struct}    {1×79 struct}    {1×64 struct}    {1×72 struct}    {1×68 struct}    {1×73 struct}    {1×80 struct}    {1×88 struct}    {1×78 struct}

  Columns 144 through 150

    {1×79 struct}    {1×76 struct}    {1×68 struct}    {1×75 struct}    {1×68 struct}    {1×68 struct}    {1×74 struct}

Voss 2023-2-7

编辑：Voss 2023-2-7

在 MATLAB Online 中打开

table.mat

You're welcome!

Note that I made selected a cell array because I assume you want to keep the trials separated (i.e., each cell of selected contains a struct array representing one trial), but if that's not the case, you can make selected itself a struct array:

load table
selected_trial_idx = [];
for ii = 1:numel(trial_table)
    msg = {trial_table(ii).trial.message};
    idx = strcmp(msg,'1');
    if any(idx)
        selected_trial_idx(end+1) = ii;
    end
end
selected = [trial_table(selected_trial_idx).trial]; % use [] instead of {}
disp(selected);
  1×11194 struct array with fields:

    message
    time
    code
    reltime
    pvel

JCH 2023-2-8

Thx, if I also want to mark their trials, saying these data are from trial 1 or 2, what should I do. Thank you again!

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Answer 2

Matt J 2023-2-7

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1908090-how-to-select-fields-of-a-struct-that-contains-certain-string#answer_1165695

编辑：Matt J 2023-2-7

在 MATLAB Online 中打开

table.mat

load table
for i=1:numel(trial_table)
  s=trial_table(i).trial;
  [~,loc]=ismember({'1','2'},{s.message});
  result(i)=s(loc(loc~=0));
end
result
result = 1×300 struct array with fields:
    message
    time
    code
    reltime
    pvel