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Unable to meet integration tolerances without reducing the step size problem.

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Md. Golam Zakaria
评论： Torsten 2023-2-7
Hello Everyone.
I am facing 'Warning: Failure at t=0.000000e+00. Unable to meet integration tolerances without reducing the step size below the smallest value allowed (7.905050e-323) at time t, error for the following code. How can I fix it.
clc
clear all
A =1.4036e-18;
B = 3.4302e-18;
e=1.60217663e-19;
T_e=3;
f = @(t,x) [(sqrt(A/x(1)))*(-x(4)-(0.424)+(1.6977)*exp(-(e/T_e)*(x(1))));
(sqrt(A/x(1)))*(x(4)-(0.663)+(2.6540)*exp(-(e/T_e)*(x(2))));
-(2.994*10^5)*x(4);
((x(1))-(x(2))+x(3)+60*(cos(t)))-2.55*10^7*x(4)];
[t,xa] = ode15s(f,[0, 80],[0,0,-62,0]);
figure(1)
plot(t,xa(:,1),'Color','blue'),grid on;
title('xa1')
xlabel('t'), ylabel('Qsp (Powered Electrode Sheath Voltage)')

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回答（1 个）

Torsten
Torsten 2023-2-7
You define an initial condition for x(1) as 0, but you divide by x(1) in equations 1 and 2.
This won't work.
  3 个评论
显示 1更早的评论
Md. Golam Zakaria
Md. Golam Zakaria 2023-2-7
@Steven Lord, If I chose nonzero initial conditions will it solve my problem. I didnt do it because It takes too much time to solve
Torsten
Torsten 2023-2-7
If I chose nonzero initial conditions will it solve my problem.
Nobody knows. Just try it.

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