Loop for 1:100
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for i=1:101
A_cont(i,i:i+100)=AH(1:101);
A_low_cont(i,i:i+100)=A_low(1:101);
A_high_cont(i,i:i+100)=A_high(1:101);
B_cont(i,i:i+100)=B1(1:101);
C_cont(i,i:i+100)=C1(1:101);
end
I have this code but I'm not sure what does (i,i:i+100) would mean in this loop. Does it calculate i for every step through i+100? How would the matrix look like?
采纳的回答
A_cont is a matrix of size 101 x 201.
In row i of A_cont, the array AH(1:101) is stored in columns i to i+100 (thus in the part in and above the diagonal) for all i ranging from 1 to 101.
The lower diagonal part of A_cont consists of zeros.
Same for the other matrices involved.
2 个评论
Marko Niko
2023-2-14
AH = rand(1,101);
A_cont = zeros(101,201);
for i = 1:101
A_cont(i,i:i+100)=AH(1:101);
end
spy(A_cont)
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