0 个投票

>> fid=fopen('firstone.txt''w')
fid =
-1
>> fid=fopen('firstone.txt','w')
fid =
3
>> for i=1:3 fprintf(fid,'The loop variable is %d\n', i) end
ans =
23
ans =
23
ans =
23
>> fclose(fid)
ans =
0
>> while~feof(fid)
aline=fget1(fid)
end
??? Error using ==> feof Invalid file identifier. Use fopen to generate a valid file identifier.
>> fid=fopen('firstone.txt')
fid =
3
>> while~feof(fid)
aline=fget1(fid)
end
??? Undefined function or method 'fget1' for input arguments of type 'double'.
>>
What went wrong and I also wonder if the three answers equal 23 after creating the text means that anything is wrong?

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 采纳的回答

Walter Roberson
Walter Roberson 2011-10-24

0 个投票

The routine name is fgetl ending with a lower-case L, not fget1 ending with the digit One.
The 23 just means that fprintf() wrote 23 characters to the file.

更多回答（1 个）

garima chandel
garima chandel 2014-8-6

0 个投票

??? Undefined function or method 'fgetline' for input arguments of type 'double'.
Error in ==> fgetl at 23 y = fgetline(fid);
Error in ==> eeg_getversion at 40 fgetl(fid);
Error in ==> eeglab>eeg_mainfig at 1202 W_MAIN = figure('Units','points', ...
Error in ==> eeglab at 449 javaobj = eeg_mainfig(onearg);
Getting error while loading eeglab command. Please help.

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