Finding row index in a matrix in which the sum of the elements is greater than 1

S=[1,0,0;0,1,0;1,1,0;0,1,1;0,0,1]
S = 5×3
     1     0     0
     0     1     0
     1     1     0
     0     1     1
     0     0     1
sum(S,2) % sum of the rows
ans = 5×1
     1
     1
     2
     2
     1
sum(S,2) > 1 % testing if they exceed 1
ans = 5×1 logical array
   0
   0
   1
   1
   0
find(sum(S,2) > 1) % which rows satisfy that requirement?
ans = 2×1
     3
     4

When you have a problem that is larger than your current abilities, break it into small, managable pieces. Solve each part, one at a time. Then put it all together. Eat a programming elephant one byte at a time.

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Answer 2

Mathieu NOE 2023-2-17

0
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hello

here you are

S=[1,0,0;0,1,0;1,1,0;0,1,1;0,0,1]
S = 5×3
     1     0     0
     0     1     0
     1     1     0
     0     1     1
     0     0     1
row_sum = sum(S,2);
rw_ind = find(row_sum>1)
rw_ind = 2×1
     3
     4