# Extracting rows form a matrix with indices.

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Paola 2023-2-21

HI all,
i have a Matrix a=(24X30) and a vector b=(1,4,7,8,10,12) that represents the rows index. I would like to create a new Matrix C=(6X30). This matrix is composed of the 6 rows with indeces (1,4,7,8,10,12), the vector b.
How can I do that?
Thanks

### 采纳的回答

dpb 2023-2-21

M=[[1:24].' randi(100,24,5)]; % a sample array
b=[1,4,7,8,10,12]; % the indexing vector
N=M(b,:) % the new array
N = 6×6
1 57 8 36 5 76 4 84 18 83 22 27 7 5 28 43 98 24 8 46 27 91 59 88 10 2 98 51 46 36 12 91 21 100 33 33
illustrates vector indirect addressing does work.
NOTA BENE: the array M was created such that the first element is the row index value so can see which was selected by inspection to prove got what wanted...
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dpb 2023-2-21
M=[[1:24].' randi(100,24,5)]; % a sample array
b=[1,4,7,8,10,12]; % the indexing vector
ix=randperm(numel(b)) % let's shuffle them around...
ix = 1×6
5 4 2 3 1 6
N=M(b(ix),:)
N = 6×6
10 24 28 71 27 13 8 65 32 13 32 84 4 97 77 44 19 36 7 33 25 48 6 49 1 7 1 28 73 63 12 14 40 79 94 88
illustrates the addressing doesn't have to be in any specific order, either...
Paola 2023-2-23
Thanks! It works

### 更多回答（1 个）

% Create Matrix A: 24 x 30
A = randi(100,[24 30]);
% Create Vector B: desired row indices
B = [1,4,7,8,10,12];
% Create Matrix C: desired rows from Matrix A, specified by B
C = A(B,:);
The desired rows are specified by B, all columns are specified by ':'.

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