Someone please help to rectify this error: Error using barrier Objective function is undefined at initial point. Fmincon cannot continue. Optimization problem

12 次查看(过去 30 天)
I want to fit the mathematical model containing double numerical integration with the data. Please help me!
This is the driver code:
clc;
clear all;
u = load("thoracicdata11.mat");
xdata11 = u.Figure9S11(1:225,1);
ydata11 = u.Figure9S11(1:225,2);
x0=[5 2 1 0.01 0.1];%
lb=[0.001 0.001 0.001 1 0.0];
ub=[100.0 200.0 100.0 100 pi/2];
options = optimset('Display', 'iter', 'MaxIter', 100, 'TolFun', 1e-6);
obj = obj_GOHGR_planar(x0,xdata11,ydata11)
Warning: Non-finite result. The integration was unsuccessful. Singularity likely.
Warning: Non-finite result. The integration was unsuccessful. Singularity likely.
Index in position 2 exceeds array bounds. Index must not exceed 1.

Error in solution>obj_GOHGR_planar (line 19)
obj = sum((ydata11(:,2)-BiaxialResponse).^2);
%[x, fval]=fmincon(@(x)obj_GOHGR_planar(x,xdata11,ydata11),x0,[],[],[],[],lb,ub,[],options);
This is the objective function:
function obj=obj_GOHGR_planar(x,xdata11,ydata11)
%xdata11 = Figure9S11(1:225,1);
%ydata11 = Figure9S11(1:225,2);
BiaxialResponse=zeros(size(xdata11(:,1)));
for i=1:size(xdata11(:,1))
BiaxialResponse(i)= BiaxialNewInvariantFunc11(x,xdata11(i,1));
end
obj = sum((ydata11(:,2)-BiaxialResponse).^2);
end
Calling function:
function K1 = BiaxialNewInvariantFunc11(par,lambda1)
integrand=@(par,lambda1,theta,phi) (3/4).*exp(1).^((1/64).*lambda1.^(-12).*(1+(-2).*lambda1.^4+ ...
lambda1.^6+(-1).*((-1)+lambda1.^6).*cos(2.*theta)+ ...
lambda1.^4.*(lambda1.^(-8).*(2.*((-1)+lambda1.^2).^2.*(1+2.* ...
lambda1.^2+lambda1.^4+lambda1.^8)+(-2).*((-1)+2.*lambda1.^4+ ...
(-2).*lambda1.^10+lambda1.^12).*cos(2.*theta))).^(1/2)).^3.* ...
par(4)+2.*cos(phi+(-1).*par(5)).^2.*par(2).*sin( ...
theta).^2).*lambda1.^(-8).*(2.*pi).^(-1/2).*(1+(-2).* ...
lambda1.^4+lambda1.^6+(-1).*((-1)+lambda1.^6).*cos(2.*theta) ...
+lambda1.^4.*(lambda1.^(-8).*(2.*((-1)+lambda1.^2).^2.*(1+ ...
2.*lambda1.^2+lambda1.^4+lambda1.^8)+(-2).*((-1)+2.* ...
lambda1.^4+(-2).*lambda1.^10+lambda1.^12).*cos(2.*theta))) ...
.^(1/2)).^2.*erfi(2.^(1/2).*par(2).^(1/2)).^(-1).*par( ...
1).*par(2).^(1/2).*par(3).*sin(theta).*((1/2).* ...
lambda1.^2.*cos(phi).^2.*sin(theta).^2.*(1+((-1)+lambda1.^2) ...
.*(lambda1.^(-8).*((-1)+lambda1.^2).^2.*((1+lambda1.^2).^2.* ...
cos(theta).^2+lambda1.^8.*sin(theta).^2)).^(-1/2))+(-1/2).* ...
lambda1.^(-4).*cos(theta).^2.*(1+lambda1.^(-4).*(1+(-1).* ...
lambda1.^4).*(lambda1.^(-8).*((-1)+lambda1.^2).^2.*((1+ ...
lambda1.^2).^2.*cos(theta).^2+lambda1.^8.*sin(theta).^2)).^( ...
-1/2)));
K1 = 0.3E0.*((-1).*lambda1.^(-4)+lambda1.^2)+ integral2(@(phi,theta) integrand(par,lambda1,theta,phi),0,2*pi,0,pi);
end
Thanks in advance! :)

回答(1 个)

Steven Lord
Steven Lord 2023-2-22
We can't run your code as we don't have all of the functions it uses, but what do you receive as an answer when you call obj_GOHGR_planar using the x0 you pass into fmincon as the input? I've commented out the call below because I want to run later code in this answer, but I wanted to show what I want you to run.
%{
y = obj_GOHGR_planar(x0)
%}
But I see another problem with your code that may be related. Does your initial point satisfy your lower and upper bounds?
x0=[5 2 1 0.01 0.1];%
lb=[0.001 0.001 0.001 1 0.0];
ub=[100.0 200.0 100.0 100 pi/2];
isx0InBounds = (lb <= x0) & (x0 <= ub)
isx0InBounds = 1×5 logical array
1 1 1 0 1
Are you sure the fourth element of x0 should be 0.01?

类别

Help CenterFile Exchange 中查找有关 Get Started with Curve Fitting Toolbox 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by