How to find a circle segment within a matlab function

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Mikael
Mikael 2023-2-22
回答： Image Analyst 2023-2-23
I need to create a function that will find the length of the arc of a circle which is 2 times the length of the segment AB that is reuniting both ends of the arc. Here is my function but I know that within the loop «for» there is a mistake but I can't see where.
The function «func» is where my angle in rad is multiplied by the radius divided by 2 (i suppose this is the good function considering the informations mentionned before).
function [rep]=Arcb(theta)
Ea=1.0;
Er=0.00001;
itermax=25;
i=0;
r=1;
iflag=0;
for i=1:itermax
func=(theta)*r/2;
dfunc=r/2;
theta2=theta-(func/dfunc);
Ea=abs((theta2-theta)/theta);
if Ea<=Er
rep=theta2;
fprintf('La solution après %d itérations est %5.2\n',i,rep);
iflag=1;
break
else
rep=theta;
end
end
end
  1 个评论
Dyuman Joshi
Dyuman Joshi 2023-2-23
Please format your code properly.
Regardless of the (finite) value of theta, theta2 will always be zero -
func=(theta)*r/2;
dfunc=r/2;
theta2=theta-(func/dfunc);

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回答（1 个）

Image Analyst
Image Analyst 2023-2-23
A diagram sure would have helped. Without it about all I can suggest is the FAQ:
https://matlab.fandom.com/wiki/FAQ#How_can_I_fit_a_circle_to_a_set_of_XY_data?
https://matlab.fandom.com/wiki/FAQ#How_do_I_create_an_arc?
or the attached paper.
If you have any more questions, then attach your data and code to read it in with the paperclip icon after you read this:
TUTORIAL: How to ask a question (on Answers) and get a fast answer

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