how to plot a mean line in a plot

5 次查看(过去 30 天)
Hello everyone!
Could you please help me with a plot. When I plot a mean v, it plots differently as 0. I need to mean line to be at the same angle as my fluctuations.
My code is:
clear all; close all;
N=100;
t = (0:N);
t1=(0:N-1);
t2=(0:N-1);
tt = rand(1,N) * 2 * pi;
ang = rand(1,N) * 2 * pi;
amp_u = 2;
amp_v = 1;
amp_w = 0.5;
u_mean=2;
v_mean=1;
w_mean=1;
u1 = amp_u.*sin(100*t2)+u_mean;
v1 = sin(ang) .* amp_v+v_mean;
w1=sin(ang) .* amp_w+w_mean;
u = cumsum([2, u1]);
x(1:N)=mean(u1);
v = cumsum([2, v1]);
w = cumsum([2, w1]);
figure(1); plot(t,u);
hold on
plot(t1,x);
  1 个评论
Dyuman Joshi
Dyuman Joshi 2023-2-27
Mean will be a scalar, constant value and it plots accordingly as well.
"When I plot a mean v ..."
You are not plotting v in your code above.
"I need to mean line to be at the same angle as my fluctuations."
Can you explain what do you mean by this? Perhaps a figure will be more helpful.

请先登录,再进行评论。

采纳的回答

Star Strider
Star Strider 2023-2-27
I need to mean line to be at the same angle as my fluctuations.
You apparently want the linear regression of ‘u1’ as a function of ‘t1’ not the mean of ‘u1’.
Try this —
% clear all; close all;
N=100;
t = (0:N);
t1=(0:N-1);
t2=(0:N-1);
tt = rand(1,N) * 2 * pi;
ang = rand(1,N) * 2 * pi;
amp_u = 2;
amp_v = 1;
amp_w = 0.5;
u_mean=2;
v_mean=1;
w_mean=1;
u1 = amp_u.*sin(100*t2)+u_mean;
v1 = sin(ang) .* amp_v+v_mean;
w1=sin(ang) .* amp_w+w_mean;
u = cumsum([2 u1]);
% x(1:N)=mean(u1);
B = [t(:) ones(size(t(:)))] \ u(:); % Linear Regression Parameters
x = [t2(1) 1; t2(end) 1] * B; % Linear Regression Evaluation
v = cumsum([2, v1]);
w = cumsum([2, w1]);
figure(1)
plot(t,u)
hold on
plot(t1([1 end]),x)
ylim([0 max(ylim)])
While I am thinking about it, do you have any thoughts on my Answer to plot a graph from user input?
.

更多回答(2 个)

Askic V
Askic V 2023-2-27
Perhaps, you can use this code:
plot(t1,x.*t1);

Sylvain
Sylvain 2023-2-27
Your question is not veary clear, but I think you want to plot:
plot(t,mean(u1)*t)

标签

产品


版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by