How about matlab size function ?

Why is the size of matrix b different from the size of matrix a?
Please, any suggestions? How to fix it
________________________
a = testSizeFunction
a =
1×1 testSizeFunction array with properties: s: [2×3 double]
[M,N] = size(a)
M = 2
N = 3
b = rand(size(a))
b = 2×2
0.5167 0.2590 0.8186 0.9810

 采纳的回答

You have not overloaded the size method appropriately for the case where nargout=1:
a = testSizeFunction;
siz=size(a)
siz = 2
Try this instead:
function varargout = size(obj,varargin)
[varargout{1:nargout}] = builtin('size', obj.s, varargin{:}); % call builtin size function
end

6 个评论

You're welcome, but please Accept-click the answer to indicate that it worked.
Thank you very much, it works.
I'm glad, but please Accept-click the answer.
@Mohamed Gharbi: Please click the "Accept This Answer" button on Matt J's answer.

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Logical 的更多信息

产品

版本

R2022b

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by