Unrecognized function or variable 'yalmip'.

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Hajar Alshaikh
Hajar Alshaikh 2023-3-5
评论： Walter Roberson 2025-6-17
matlab should known sdpvar in the code becuse if i used help it give me the meaning of it but it said instead
Unrecognized function or variable 'yalmip'.
Error in sdpvar (line 518)
[mt,variabletype,hashed_monoms,current_hash] = yalmip('monomtable');
% Define the partially specified Euclidean distance matrix
D = [0 1 0 3; 1 0 2 0; 0 2 0 0; 3 0 0 0];
% Define the size of the matrix
n = size(D, 1);
% Define the optimization variables
X = sdpvar(n, n);
% Set up the optimization problem
Constraints = [X == semidefinite(n), diag(X) == zeros(n, 1), X >= 0];
Objective = sum(sum((X - D).^2));
Options = sdpsettings('solver', 'mosek');
% Solve the optimization problem
optimize(Constraints, Objective, Options);
% Extract the completed Euclidean distance matrix
D_complete = value(X);
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Hajar Alshaikh
Hajar Alshaikh 2023-3-5
I want also to check or insatll the CVX package
Luca Ferro
Luca Ferro 2023-3-6
use the command ver to find every package installed and visible

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回答（2 个）

Sachin
Sachin 2023-3-13
Hi @Hajar Alshaikh
As per my understanding you are facing issue in ‘yalmip’ implementation. Referring the following information might be of good help to you assuming that you are using MATLAB R2022b.
  1. Check if you have installed ‘yalmip’ in your system by following command in MATLAB.
V = yalmip('version'); % to check version of 'yalmip'
2. If You have not added the path after downloading the zip file.
You can refer the following information to know more about add path.
https://www.mathworks.com/matlabcentral/answers/116177-how-to-add-a-folder-permanently-to-matlab-path
https://www.mathworks.com/help/matlab/ref/addpath.html
mouhcine
mouhcine 2025-6-17
Ran in:
%% Initialisation des données
clc; clear; close all;
% 1. Données des clients (5 clients + dépôt)
clients = [
0 0 0 0 0 ; % Dépôt (id, x, y, début fenêtre, fin fenêtre)
1 2 3 8 10 ; % Client 1
2 1 5 9 12 ; % Client 2
3 4 2 10 14 ; % Client 3
4 3 6 11 15 ; % Client 4
5 5 1 13 17 ; % Client 5
];
% Temps de service (minutes)
s = [0; 15; 10; 20; 10; 15];
% Demandes (kg)
q_demand = [0; 10; 8; 12; 5; 7];
% 2. Calcul des distances
n_clients = size(clients,1);
distances = zeros(n_clients,n_clients);
for i = 1:n_clients
for j = 1:n_clients
distances(i,j) = norm(clients(i,2:3) - clients(j,2:3));
end
end
% 3. Données des camions (5 véhicules)
camions = [
200 40 0.30 20 ;
300 45 0.35 30 ;
150 50 0.25 15 ;
250 35 0.40 25 ;
350 40 0.45 35 ;
];
%% Modélisation YALMIP
n_camions = size(camions,1);
% Variables
x = binvar(n_clients,n_clients,n_camions,'full'); % Trajets
t = sdpvar(n_clients,1); % Temps d'arrivée
y = binvar(n_camions,1); % Camion utilisé
% Contraintes
C = [];
% Chaque client visité une fois (sauf dépôt)
for i = 2:n_clients
C = [C, sum(sum(x(i,:,:),3) == 1];
Unmatched ']'. Check for missing '['.
end
% Équilibre de flux
for k = 1:n_camions
for p = 1:n_clients
C = [C, sum(x(:,p,k)) == sum(x(p,:,k))];
end
end
% Capacité
for k = 1:n_camions
C = [C, sum(q_demand'.*squeeze(x(2:end,:,k))) <= camions(k,1)];
end
% Fenêtres temporelles
for i = 2:n_clients
C = [C, clients(i,4) <= t(i) <= clients(i,5)];
end
% Calcul des temps
M = 24; % Big-M
for k = 1:n_camions
for i = 1:n_clients
for j = 1:n_clients
if i ~= j
C = [C, t(j) >= t(i) + s(i)/60 + distances(i,j)/camions(k,2) - M*(1-x(i,j,k))];
end
end
end
end
% Activation camions
for k = 1:n_camions
C = [C, sum(x(1,:,k)) == y(k)];
end
%% Objectifs
cout_total = 0;
for k = 1:n_camions
cout_total = cout_total + sum(sum(distances.*camions(k,3).*x(:,:,k))) + camions(k,4)*y(k);
end
temps_total = max(t(2:end) + s(2:end)/60);
%% Résolution
options = sdpsettings('solver','gurobi','verbose',1);
optimize(C, cout_total + 0.1*temps_total, options); % Pondération arbitraire
%% Affichage des résultats
if value(cout_total) > 0
disp('=== Solution trouvée ===');
disp(['Coût total: ', num2str(value(cout_total)), ' €']);
disp(['Temps total: ', num2str(value(temps_total)), ' heures']);
% Visualisation des tournées...
else
disp('Aucune solution trouvée');
end
  1 个评论
Walter Roberson
Walter Roberson 2025-6-17
C = [C, sum(sum(x(i,:,:),3) == 1];
% 1 2 3 2 1
The digits are the nesting level "after" the character above in the expression.
Notice that at the end, the active nesting level is 1, instead of 0. You are missing a ) somewhere in the expression. You probably wanted
C = [C, sum(sum(x(i,:,:),3)) == 1];
or more simply,
C = [C, sum(x(i,:,:),"all") == 1];

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