Evaluating all possible combinations

I am working on designing a composite part. The two main variables are the number of layers i can stack and the orientation of each layer (0,45,90 deg.). In the below image, we can see different layers stacked with different orientations
I am trying to find all possible sequences that can be made, but im not sure how to go about that. For example, if i have 5 layers, how would i determine all the possible sequences?
I've tried perms and nchoosek - don't seem to work, but im not sure why.
Thanks

2 个评论

So for each layer you have 4 possible orientations. Thus if you have N layers, the number of possible arrangements is 4^N. Is this a correct interpretation of what you try to achieve ?
Yes, i believe that's the proper understanding.

请先登录,再进行评论。

 采纳的回答

See below for one method to obtain all combinations.
In the resulting matrix, each row represents a combination, the first column holds the angle for the first layers, the second for the second etc.
Hope it helps ;)
% define the angle options for a layer
LayerOptions = [0 -45 45 90];
% define number of layers
NumLayer = 5;
% create place holder for the layers
CellCombo = cell(1,NumLayer);
% assign the options for each layer
CellCombo(:) = {LayerOptions};
% extend the data to obtain the combinations
Combinations = CellCombo;
[Combinations{:}] = ndgrid(CellCombo{:});
Combinations = cell2mat(cellfun(@(m)m(:),Combinations,'uni',0));
% print the result
Combinations
Combinations = 1024×5
0 0 0 0 0 -45 0 0 0 0 45 0 0 0 0 90 0 0 0 0 0 -45 0 0 0 -45 -45 0 0 0 45 -45 0 0 0 90 -45 0 0 0 0 45 0 0 0 -45 45 0 0 0

1 个评论

This helps a lot, thanks! It does exactly what I was looking for.
I do appreciate your help!

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Matrix Indexing 的更多信息

产品

版本

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by