split array to subarray and save it as csv file

2 次查看(过去 30 天)
Hi,
I have a csv file 6 x1086 I want to split it to 181 csv files each files 6x6 and save those files.
the first csv file will have the first 6 columns 1:6 , the second csv file will have the second 6 columns i.e. 7:12 ...etc.
I want to give name for each csv file for example: result1.csv , result2.csv ,...,result181.csv
Can you please help me with that. Thanks in advance

采纳的回答

Voss
Voss 2023-3-7
fn = 'your\csv\file.csv';
pn = 'folder\where\you\want\the\results\to\go';
n = 6;
C = readcell(fn);
for ii = 1:size(C,2)/n
writecell(C(:,(ii-1)*n+(1:n)),fullfile(pn,sprintf('result%d.csv',ii)));
end
  6 个评论
Az.Sa
Az.Sa 2023-3-8
编辑:Az.Sa 2023-3-8
Hi,
if my matrix C is 6 x 4005
ans I want to split it to submatrix with following formula
frist submatrix c1: the first 6x230 observations
c1=C(:,1:230);
the second submatrix c2: is 6 x 230 observations as well but I will delet the first 20 observations from c1 and keep the rest 200 and add to them the following 20 observations from C. i.e.
c2=C(:,21:250);
the third submatrix c3: 6x230 observation, we remove the first 20 observation from c2 ,keep the 200 from c2 and add the following 20 observation from C . i.e.
c3=C(:,40:270);
and so on for the rest of the submatrix. so I am expecting to have 181 submatrix.
I tried to to change n=230 but in total I received only 17 submatrix which is only taking the 230 observations from C succesively which I beleive because of the formula C(:,(ii-1)*n+(1:n) )
Can you please help how to adjust the formula. Thank you
Voss
Voss 2023-3-8
n = 230;
m = 20;
for ii = 1:(size(C,2)-n)/m+1
writecell(C(:,(ii-1)*m+(1:n)),fullfile(pn,sprintf('result%d.csv',ii)));
end
This will give you 189 sub-matrices: C(:,1:230), C(21:250), C(41:270), ..., C(3741:3970), C(3761:3990)
(3761-1)/20+1 = 189
And the last one ends with 3990 not 4005, i.e., the last 15 columns of C will be left over.

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Matrices and Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by