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How can I do a Monte Carlo simulation for 1000 runs on this operation?

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Uche
Uche 2023-3-8
评论： Uche 2023-3-11
Please can someone help to verify that this is the proper way to run a monte carlo simulation on this code?
% A = T(:,1); %Column vector
A = [71.213; 74.499; 79.175; 54.163; 83.008; 52.615];
B = length(A); %size of column (number of elements)
t = 0; %Variable to store harvest time
number_of_runs = 1000;
for n = 1:number_of_runs
for i = 1:B
H = A(i);
while H > 0
H = H - randi([5 10]);
t = t + randi([2 4]);
end
end
end
t_mean = t/number_of_runs;
disp(t_mean);
  2 个评论
John D'Errico
John D'Errico 2023-3-8
编辑：John D'Errico 2023-3-9
Hard to say. That is the proper way to simulate what you simulated. Is it the proper way to simulate what you think you were simulating? That is impossible to tell, since we see only the code you wrote. So perhaps you need to explain what is the goal.

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采纳的回答

Torsten
Torsten 2023-3-9
Ran in:
Maybe you mean:
% A = T(:,1); %Column vector
A = [71.213; 74.499; 79.175; 54.163; 83.008; 52.615];
B = length(A); %size of column (number of elements)
number_of_runs = 1000;
T = zeros(number_of_runs,1); %Variable to store harvest time
for n = 1:number_of_runs
t = 0;
for i = 1:B
H = A(i);
while H > 0
H = H - randi([5 10]);
t = t + randi([2 4]);
end
end
T(n) = t;
end
plot(1:number_of_runs,T)
t_mean = sum(T)/number_of_runs;
disp(t_mean);
175.9570

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